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3 years ago

Which elements are considered "Noble Metals"?

Chemistry

1 answer:

Lisa [10]3 years ago

7 0

Answer:

ruthenium (Ru), rhodium (Rh), palladium (Pd), osmium (Os), iridium (Ir), platinum (Pt), gold (Au), silver (Ag).

Explanation:

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PLZ DON"T JUST PICK AN ANSWER I REALLY NEED HELP

VMariaS [17]

Answer:

60 hours

Explanation:

18.0 __15__ 9 __15__ 4.5 __15__ 2.25 __15__ 1.125g

15(4)= 60

5 0

3 years ago

What is the mass of 0.35 moles of C2H5OH (alcohol)?

sammy [17]

Explanation:

hope it make sense to u :)

3 0

3 years ago

Using only the groups of the periodic table, choose one element that is chemically similar to each of the following elements.

zhenek [66]

Elements that are in the same columns (vertical) are chemically similar.

Carbon- Si
Cesium- Na
Krypton- Ar
Magnesium- Ca
Al- try Boron
Br try Cl

These are just the ones I picked but it could be any in the same column

4 0

3 years ago

108/49 In ? 108/48 Cd + ? In the equation above, what particle or type of radiation needs to be included on the right hand side

Oksanka [162]

Answer: b) positron

Explanation:

The antiparticle or the antimatter counterpart of the electron is called positron.

The positron has an electric charge of +1 e and same mass as an electron. When a positron collides with an electron, annihilation takes place.

Below is an attachnent that further explains this

7 0

3 years ago

Complete and balance the molecular equation for the reaction of aqueous sodium carbonate, Na 2 CO 3 , and aqueous nickel(II) chl

pantera1 [17]

Answer:

NiCl2 (aq) + Na2CO3 (aq) ---> NiCO3 (s) + 2NaCl (aq)

Explanation:

Soluble ionic compounds exist as ions in solution.

Na 2CO3, will contain Na2CO3 (aq) --> 2Na ^+ (aq) + CO2 ^-3 (aq)

The same way, a solution of calcium chloride,

CaCl 2, will contain CaCl2 (aq) --> Ca2^+ (aq) + 2Cl^− (aq)

Mixing both solution, the calcium cations

Ca 2^+ , will apir up with the carbonate anions, CO2^−3 , and form the Insoluble calcium carbonate, CaCO ^3, which precipitates out of solution.

The complete ionic equation, which features all the ions that are present in solution, will be like this

2 Na^+ (aq) + CO2^−3 (aq) + Ca2^+ (aq) + 2Cl^− (aq) --> CaCO 3 ↓ (s) + 2Na^+ (aq) + 2Cl^− (aq)

Notice that you have two sodium cations and two chloride anions on the products' side, which is why you have 2NaCl

NiCl2 (aq) + Na2CO3 (aq) ---> NiCO3 (s) + 2NaCl (aq)

4 0

3 years ago