Answer:
b) 6
Explanation:
Given
v(t)=3t²+6t
X(0) = 2
X(1) = ?
Knowing that
v(t)=3t²+6t = dX/dt
⇒ ∫dX = ∫(3t²+6t)dt
⇒ X - X₀ = t³ + 3t²
⇒ X(t) = X₀ + t³ + 3t²
If X(0) = 2
⇒ X(0) = X₀ + (0)³ + 3(0)² = 2
⇒ X₀ = 2
then we have
X(t) = t³ + 3t² + 2
when
t = 1
X(1) = (1)³ + 3(1)² + 2
X(1) = 6
Answer:
The component of block weight parallel to the plane, Wₓ = W cosθ
Explanation:
Let the weight of the block due to gravitation is W
The direction of the weight is vertically down
Let θ be the angle formed with the vertical weight of the block and the incline.
Taking two components of weight one along the vertical weight and another component perpendicular to it.
Then the component `of weight long the parallel of the plane is
Wₓ = W cosθ
By God wanting them to be the same kinda
I\B
2/A
3\C
4\E
5\D
6\F
I think this is right
We can calculate his resultant speed.
Resultant speed is:
v^2 = 5^2 + 1,9^2
v = 5,349 m/s
Now we need to find angle between resultant speed and vertical speed.
cos(alpha) = 5/5.349 = 0.9347
alpha = 20,8 degrees
Answer is 20,8 degrees