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schepotkina [342]
3 years ago
15

A company makes traffic signs one of those signs can be modeled by an equilateral triangle with the perimeter of 144 inches the

company makes the summer sun with a perimeter that is 1.25 times the one above what is the height in inches of the larger

Mathematics
1 answer:
barxatty [35]3 years ago
4 0

Answer:

The height of the larger traffic signs is 51.96 inches

Step-by-step explanation:

Given that initially, A company makes traffic signs of an equilateral triangle with the perimeter of 144 inches

Now, A company makes similar traffic signs of perimeter 1.25 of original

New perimeter will be 1.25x144=180 inches

Let triangle ABC be a larger triangle with 180inches of the perimeter.

It is given that the triangle is an equilateral triangle,

Therefore, Side AB=BC=AC

The perimeter of a triangle ABC is

AB+BC+AC=180

3AB=180

AB=60 inches

Figure show that triangle ABC and AD is the height of the triangle.

Since, the triangle ABC is an equilateral triangle,

AD is the perpendicular bisector of BC

so that,

BD=DC and Angle ADB=90

In right triangle ADB,

Angle D =90 and Angle B =60

Side BD=60/2=30 inches and AB=60 inches

Using Pythagoras theorem,

AD^{2} +BD^{2} =AC^{2}

(AD)^{2} +(30)^{2} =60^{2}

(AD)^{2} =60^{2}-(30)^{2}

AD=51.96 inches

Thus, The height of the larger traffic signs is 51.96 inches

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It is a function

Step-by-step explanation:

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Hello, how was your day, help? ^ ^<br> solve for x
Natali5045456 [20]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

\boxed{x=100}

»»————- ★ ————-««  

Here’s why:  

  • Recall the Triangle Angle Sum Theorem: The three angles of all triangles add up to a sum of 180°.
  • We will set up an equation based on this and then solve.

⸻⸻⸻⸻

\boxed{\text{Solve for 'x':}}\\\\58 + 22 + x = 180\\-----------\\\rightarrow 80 + x = 180\\\\\rightarrow 80 - 80 + x = 180 - 80\\\\\rightarrow \boxed{x=100}

⸻⸻⸻⸻

»»————- ★ ————-««  

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6 0
2 years ago
Could you please look at this question?
MrMuchimi

Answer:

  a. see attached

  b. H(t) = 12 -10cos(πt/10)

  c. H(16) ≈ 8.91 m

Step-by-step explanation:

<h3>a.</h3>

The cosine function has its extreme (positive) value when its argument is 0, so we like to use that function for circular motion problems that have an extreme value at t=0. The midline of the function needs to be adjusted upward from 0 to a value that is 2 m more than the 10 m radius. The amplitude of the function will be the 10 m radius. The period of the function is 20 seconds, so the cosine function will be scaled so that one full period is completed at t=20. That is, the argument of the cosine will be 2π(t/20) = πt/10.

The function describing the height will be ...

  H(t) = 12 -10cos(πt/10)

The graph of it is attached.

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<h3>b. </h3>

See part a.

__

<h3>c.</h3>

The wheel will reach the top of its travel after 1/2 of its period, or t=10. Then 6 seconds later is t=16.

  H(16) = 12 -10cos(π(16/10) = 12 -10cos(1.6π) ≈ 12 -10(0.309017) ≈ 8.90983

The height of the rider 6 seconds after passing the top will be about 8.91 m.

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2 years ago
All parallelograms are _____
Natali5045456 [20]

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Step-by-step explanation:

8 0
3 years ago
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Rewrite in simplest radical form, thx :)
Aleks [24]

Answer:

The answer is

\sqrt[3]{ {x}^{2} }

Step-by-step explanation:

\frac{ {x}^{ \frac{5}{6} } }{ {x}^{ \frac{1}{6} } }

Since they have the same base and are dividing we can use the rules of indices

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subtract the exponents

So we have

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We have the final answer as

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Hope this helps you

6 0
3 years ago
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