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Zolol [24]
3 years ago
5

You are performing a gradient elution and are instructed to begin with a low polarity solvent (petroleum ether) and continue to

increase solvent polarity with MTBE. Why are the mobile phases added in order of increasing polarity rather than in the order of decreasing polarity?
Chemistry
1 answer:
Sophie [7]3 years ago
3 0

Answer:

The eluting strength of a solvent is primarily related to how strongly it adsorbs onto the  adsorbent and because typical adsorbents are highly polar; thus, eluting strength increases  with solvent polarity.

Explanation:

The polarity of a solvent makes it more suitable for elution in a polar adsorbent. Hence the choice of solvents should be in order of increasing rather than decreasing polarity. polarity must increase and not decrease

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When the following equation is balanced, what is the coefficient for NaNO3?
notka56 [123]

The coefficient for NaNO₃ = 6

<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

AI(NO₃)₃ +Na₂SO₄ → Al₂(SO₄) + NaNO₃

give coefficient

aAI(NO₃)₃ +bNa₂SO₄ → Al₂(SO₄)₃ +c NaNO₃

Al, left=a, right=2⇒a=2

N, left=3a, right=c⇒3a=c⇒3.2=c⇒c=6

Na, left=2b, right=c⇒2b=c⇒2b=6⇒b=3

The equation becomes :

2AI(NO₃)₃ +3Na₂SO₄ → Al₂(SO₄)₃ +6NaNO₃

6 0
3 years ago
Naturally occurring element X exists in three isotopic forms: X-28 (27.979 amu, 92.21% abundance), X-29 (28.976 amu 4.70% abunda
bezimeni [28]

<u>Answer:</u> The average atomic mass of X is 28.09 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i .....(1)

  • <u>For isotope 1:</u>

Mass of isotope 1 = 27.979 amu

Percentage abundance of isotope 1 = 92.21 %

Fractional abundance of isotope 1 = 0.9212

  • <u>For isotope 2:</u>

Mass of isotope 2 = 28.976 amu

Percentage abundance of isotope 2 = 4.70 %

Fractional abundance of isotope 2 = 0.0470

  • <u>For isotope 3:</u>

Mass of isotope 3 = 29.974 amu

Percentage abundance of isotope 3 = 3.09 %

Fractional abundance of isotope 3 = 0.0309

Putting values in equation 1, we get:

\text{Average atomic mass of X}=[(27.979\times 0.9212)+(28.976\times 0.0470)+(29.974\times 0.0309)]

\text{Average atomic mass of X}=28.09amu

Hence, the average atomic mass of X is 28.09 amu

4 0
3 years ago
A 35,000 Newton car runs up a hill that is 45.5 meters high in 1.6 seconds. what power did it exert?
Evgesh-ka [11]

Answer:

995.313KW

Explanation:

the explanation is in the picture

please like and Mark as brainliest

7 0
3 years ago
What is the coefficient for calcium oxide? CaO(s) + CO2(g) → CaCO3(s)
VARVARA [1.3K]

Answer:

The coefficient is 1

Explanation:

CaO(s) + CO2(g) -> CaCO3(s)

In the balanced equation, the coefficient for CaO is 1

The coefficient represents the number of moles of a compound in the stoichiometry of the reaction

4 0
3 years ago
3. A thin lead apron is used to protect patients from harmful X rays. If the sheet measures 75.0 cm by 55.0 cm by 0.10 cm, and t
DanielleElmas [232]

Answer:

4.67 kg

Explanation:

Given data

  • Dimensions of the lead sheet: 75.0 cm by 55.0 cm by 0.10 cm
  • Density of lead: 11.3 g/cm³

Step 1: Calculate the volume of the sheet

The volume of the sheet is equal to the product of its dimensions.

V = 75.0 cm \times  55.0 cm \times 0.10 cm = 413 cm^{3}

Step 2: Calculate the mass of the sheet

The density (ρ) is equal to the mass divided by the volume.

\rho = \frac{m}{V} \\m = \rho \times V = \frac{11.3g}{cm^{3} }  \times 413cm^{3} = 4.67 \times 10^{3} g = 4.67 kg

6 0
3 years ago
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