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ipn [44]
3 years ago
9

The common Eastern mole, a mammal, typically has a mass of 83 g, which corresponds to about 8.3 moles of atoms. (A mole of atoms

is 6.02 × 1023 atoms. In atomic mass units (u), what is the average mass of atoms in the common Eastern mole?
Chemistry
1 answer:
Alchen [17]3 years ago
6 0

Answer:

1.6605 × 10⁻²³ g / atom , 9.99 amu

Explanation:

Atoms present in 1 mole = 6.022 × 10²³ atoms

Given that

Moles of common Eastern mole = 8.3 moles

So,

Atoms in 8.3 moles are:

8.3 moles = 6.022 × 10²³ × 8.3 atoms

Also,

Average mass = Mass of the sample / Number of atoms

Mass of sample = 83 g

Average mass = 83 g / 6.022 × 10²³ × 8.3 atoms = 1.6605 × 10⁻²³ g / atom

In amu :

1 amu = 1.66 × 10⁻²⁴ g / atom

So,

Average mass = 1.6605 × 10⁻²³ / 1.66 × 10⁻²⁴ amu = 9.99 amu

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Answer:

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Explanation:

Given data:

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Solution:

Formula:

Q = m.c. ΔT

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125 g × 4.184 j/g°C ×  (235°C - 100.0°C)  = m × 0.13 j/g°C ×  (235°C - 20°C)

125 g × 4.184 j/g°C × 135°C  = m × 0.13 j/g°C × 215°C

70605 j = m×27.95 j/g

m = 70605 j /27.95 j/g

m = 2526.12 g

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