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DENIUS [597]
3 years ago
9

I. Loosening of immigration policies

Chemistry
1 answer:
hoa [83]3 years ago
5 0

Answer:

I think it is III I hope this helps

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A 0.600 g sample of diprotic acid H2X is dissolved in water, and titrated to the equivalence point with 40.0 mL of 0.200 M NaOH.
9966 [12]

Answer:

150 g/mol

Explanation:

Let's consider the complete neutralization of a diprotic acid H₂X with NaOH.

H₂X + 2 NaOH → Na₂X + 2 H₂O

40.0 mL of 0.200 M NaOH. were required to reach the endpoint. The reacting moles of NaOH are:

0.0400 L × 0.200 mol/L = 8.00 × 10⁻³ mol

The molar ratio of H₂X to NaOH is 1:2. The reacting moles of H₂X are 1/2 × 8.00 × 10⁻³ mol = 4.00 × 10⁻³ mol.

4.00 × 10⁻³ moles of H₂X have a mass of 0.600 g. The molar mass of H₂X is:

0.600 g/4.00 × 10⁻³ mol = 150 g/mol

8 0
3 years ago
Example of oxidizing agents include
Ivahew [28]

Explanation:

Substances generally tends to specialize as either oxidizing or reducing agents.

An oxidizing agent is an electron acceptor which causes a co-reactant to be oxidized in a reaction.

Examples are:

   Non-metals especially oxygen and the halogens.

Other examples are H₂SO₄ , HNO₃, KMnO₄, K₂Cr₂O₇

learn more:

Oxidizing and reducing agents brainly.com/question/5558762''

#learnwithBrainly

4 0
4 years ago
A gaseous sample of pure methane, CH4, is found to occupy a volume of 20.0 L at 25℃ and 1 atm pressure. What volume of O2, at th
alexdok [17]
None of the above is the correct answer
7 0
4 years ago
How is atomic number and mass related to protons, neutrons, & electrons?
artcher [175]
The atomic number is the numbers of protons

6 0
4 years ago
Read 2 more answers
If 30.0 g absorbs 255 J of heat, how much does the temperature of the water change? Would the temperature be increasing or decre
Nutka1998 [239]
<h3>Answer:</h3>

Change in temperature = 2.03°C, the temperature is increasing

<h3>Explanation:</h3>
  • To calculate the quantity of heat absorbed or released by a substance we multiply mass of the substance by it's specific heat capacity and the temperature change.
  • Therefore, Quantity of heat, Q = mass × specific heat × change in temperature

In this case;

Mass of water = 30.0 g

Quantity of heat absorbed = 255 J

Specific heat capacity of water = 4.186 J/g°C

Rearranging the formula, Δt = Q ÷ mc

Δt = 255 J ÷ (4.186 J/g°C×30.0 g )

  = 2.03 °C

The temperature change is 2.03°C, the temperature is therefore increasing.

3 0
3 years ago
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