Answer:
150 g/mol
Explanation:
Let's consider the complete neutralization of a diprotic acid H₂X with NaOH.
H₂X + 2 NaOH → Na₂X + 2 H₂O
40.0 mL of 0.200 M NaOH. were required to reach the endpoint. The reacting moles of NaOH are:
0.0400 L × 0.200 mol/L = 8.00 × 10⁻³ mol
The molar ratio of H₂X to NaOH is 1:2. The reacting moles of H₂X are 1/2 × 8.00 × 10⁻³ mol = 4.00 × 10⁻³ mol.
4.00 × 10⁻³ moles of H₂X have a mass of 0.600 g. The molar mass of H₂X is:
0.600 g/4.00 × 10⁻³ mol = 150 g/mol
Explanation:
Substances generally tends to specialize as either oxidizing or reducing agents.
An oxidizing agent is an electron acceptor which causes a co-reactant to be oxidized in a reaction.
Examples are:
Non-metals especially oxygen and the halogens.
Other examples are H₂SO₄ , HNO₃, KMnO₄, K₂Cr₂O₇
learn more:
Oxidizing and reducing agents brainly.com/question/5558762''
#learnwithBrainly
The atomic number is the numbers of protons
<h3>
Answer:</h3>
Change in temperature = 2.03°C, the temperature is increasing
<h3>
Explanation:</h3>
- To calculate the quantity of heat absorbed or released by a substance we multiply mass of the substance by it's specific heat capacity and the temperature change.
- Therefore, Quantity of heat, Q = mass × specific heat × change in temperature
In this case;
Mass of water = 30.0 g
Quantity of heat absorbed = 255 J
Specific heat capacity of water = 4.186 J/g°C
Rearranging the formula, Δt = Q ÷ mc
Δt = 255 J ÷ (4.186 J/g°C×30.0 g )
= 2.03 °C
The temperature change is 2.03°C, the temperature is therefore increasing.