The area-
The area under the line in a velocity-time graph represents the distance travelled. To find the distance travelled in the graph above, we need to find the area of the light-blue triangle and the dark-blue rectangle.
<span><span>Area of light-blue triangle -
<span>The width of the triangle is 4 seconds and the height is 8 meters per second. To find the area, you use the equation: <span>area of triangle = 1⁄2 × base × height </span><span>so the area of the light-blue triangle is 1⁄2 × 8 × 4 = 16m. </span></span></span><span> Area of dark-blue rectangle
The width of the rectangle is 6 seconds and the height is 8 meters per second. So the area is 8 × 6 = 48m.</span><span> Area under the whole graph
<span>The area of the light-blue triangle plus the area of the dark-blue rectangle is:16 + 48 = 64m.<span>This is the total area under the distance-time graph. This area represents the distance covered.</span></span></span></span>
Answer:
Angular velocity (w) = 8.86 rad/s
Explanation:
Angular velocity (w) = 
g= 9.81 m/s
R= 0.5
hi (initial depth) = 0.5m
Hence= 
= 8.86 rad/s
Answer:
B and B
Explanation:
Question 1:
The distance is a unit of length, such as miles, meters, kilometers
The correct answer for this question would be 8m
Question 2:
Speed has a unit of length per unit of time.
The correct answer for this would be meters per second
-Chetan K
Answer:
Explanation:
As we know that the sixth order maximum will have path difference given as
here we know that
N = order of maximum
now we have
so we know that
