Answer:
1.90×10²⁰ Electrons
Explanation:
From the question,
Q = It.................... Equation 1
Where Q = charge flowing through the wire, I = current, t = time
Given: I = 4.35 A, t = 7.00 s
Substitute these values into equation 1
Q = 4.35(7.00)
Q = 30.45 C.
But,
1 electron contains 1.6×10⁻¹⁹ C
therefore,
30.45 C = 30.45/1.6×10⁻¹⁹ electrons
= 1.90×10²⁰ Electrons
Answer: 50.7 J
Explanation:
Given
mass of lion is 
The initial speed of the lion is 
increased speed of lion is 
Initially, its kinetic energy is 
Final kinetic energy 
work did by lion after speed up is 
![\Rightarrow W=\dfrac{1}{2}\times 2.6[8^2-5^2]\\\\\Rightarrow W=1.3\times [39]=50.7\ J](https://tex.z-dn.net/?f=%5CRightarrow%20W%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202.6%5B8%5E2-5%5E2%5D%5C%5C%5C%5C%5CRightarrow%20W%3D1.3%5Ctimes%20%5B39%5D%3D50.7%5C%20J)
v2 = ?
m1 = 10kg
m2 = 70kg
v1 = 4m/s
E1 = E2
E1 = 1/2 * m1 * v1^2 = 1/2 * 10kg * 4m/s^2 = 80J
E2 = 1/2 * m2 * v2^2 = 80 J
v2 = √(E2/(2 * m2)) = √(80J/(2 * 70kg)) = about 0.76m/s
Answer:
37500 J
Explanation:
Law of conservation of energy: Its states that energy can neither be created nor destroyed but it can be transformed from one form to another.
Applying the law of conservation of energy.
The change in kinetic energy for the truck = Net work done by the truck skids
ΔK.E = F×d.................... Equation 1
Where ΔK.E = Change in kinetic energy, F = Force, d = distant.
Given: F = 1500 N, d = 25 m
Substitute these values into equation 1
ΔK.E = 1500×25
ΔK.E = 37500 J
