<span>The pythagorean theorem addresses the length of the hypotenuse in relation to the length of the legs. The square root of the length of the hypotenuse is equal to the sum of one leg squared plus the other leg squared. In other words, A squared plus B squared equals C squared where A and B are the lengths of the legs of the triangle and C is the length of the hypotenuse.</span>
        
                    
             
        
        
        
Answer:
D
Explanation:
Political scientists use political models to describe the political climate, which is an aggregate mood or opinion of a political society at a point in time.
 
        
                    
             
        
        
        
Answer:
<em>The force of friction acting on the block has a magnitude of 15 N and acts opposite to the applied force.</em>
Explanation:
<u>Net Force
</u>
The Second Newton's law states that an object acquires acceleration when an unbalanced net force is applied to it.
The acceleration is proportional to the net force and inversely proportional to the mass of the object.
If the object has zero net force, it won't get accelerated and its velocity will remain constant.
The m=2 kg block is being pulled across a horizontal surface by a force of F=15 N and we are told the block moves at a constant velocity. This means the acceleration is zero and therefore the net force is also zero.
Since there is an external force applied to the box, it must have been balanced by the force of friction, thus the force of friction has the same magnitude acting opposite to the applied force.
The force of friction acting on the block has a magnitude of 15 N opposite to the applied force.
 
        
             
        
        
        
Answer:
The magnitude of the acceleration is 
The direction is   north of  east
 north of  east 
Explanation:
From the question we are told that 
    The force exerted by the wind is  
    The force exerted by water is  
       The mass of the boat(+ crew) is   
 
Now Force is mathematically represented as 
       
Now the acceleration towards the north is mathematically represented as 
       
 substituting values 
        
       
Now the acceleration towards the east is mathematically represented as 
        
 substituting values 
       
       
The resultant acceleration is  
       
substituting values 
      
       
The direction with reference from the north is evaluated as 
Apply SOHCAHTOA
         
        ![\theta = tan ^{-1} [\frac{a_e}{a_n } ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%20%5E%7B-1%7D%20%5B%5Cfrac%7Ba_e%7D%7Ba_n%20%7D%20%5D)
 substituting values
      ![\theta = tan ^{-1} [\frac{0.808}{1.269 } ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%20%5E%7B-1%7D%20%5B%5Cfrac%7B0.808%7D%7B1.269%20%7D%20%5D)
     ![\theta = tan ^{-1} [0.636 ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%20%5E%7B-1%7D%20%5B0.636%20%5D)
    