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mylen [45]
3 years ago
6

SOMEONE PLSSSS HELP ME WITH THIS QUESTION!!

Physics
1 answer:
Hitman42 [59]3 years ago
4 0
The answer is indeed B
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A split highway has a number of lanes for traffic. For traffic going in one direction, the radius for the inside of the curve is
Andrew [12]

Answer:

The correct one is that the force on B is half of the force on A

Explanation:

Because radius for the inside of the curve is half the radius for the outside and Car A travels on the inside while car B, travels at equal speed on the outside of the curve. Thus force on B will be half on A

3 0
3 years ago
It took 1500 Newton's of force to push a car 3 meters. How much work was done
denis23 [38]

Answer:

ow much work was done? W = F xD. IN X 2m = 2;. 2. A force of 15 newtons is ... 3. It took 50 joules to push a chair 5 meters across the floor. With what force was ... was done. How far was the rock lifted? W=FXD. D=1500 = 1.5m. Answer: :.5m ... A young man exerted a force of 9,000 newtons on a stalled car, but he was.

Explanation:

3 0
3 years ago
HEY CAN ANYONE PLS ANSWER DIS RQ!!!!
Bezzdna [24]

Answer:

Negative

Explanation:

If you have to move the decimal point to the right to get the original number, the exponent will be a positive number, if you have to move the decimal point to the left to get the original number, the exponent will be a negative number.

Hope this helped!

8 0
3 years ago
Please help!
uysha [10]

Answer:

a c d

Explanation:

because I said so and yeah nshsjsisayagavava sishywabhwvsusnsbs

5 0
4 years ago
An alternating-current (AC) source supplies a sinusoidally varying voltage that can be described with the function v of t is equ
Marrrta [24]

Answer:

ω, the angular frequency of the source equals 377 rad/s

Explanation:

From the question, V(t) = V cosωt.

Now, ω = the angular frequency of the sinusoidal wave is given by

ω = 2πf where f = the frequency of the source = 60 Hz

So, the angular frequency of the source ,ω = 2π × the frequency of the source.

So, ω = 2πf

ω = 2π × 60 Hz

ω = 120π rad/s

ω = 376.99 rad/s

ω ≅ 377 rad/s

So, ω, the angular frequency of the source equals 377 rad/s

3 0
3 years ago
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