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lorasvet [3.4K]
3 years ago
13

Circuit A

Physics
2 answers:
Licemer1 [7]3 years ago
3 0
By V=IR
A: 24=I*20
I = 1.2A

B: 220 = I*250
I = 0.88A

C: 6= I*3
I = 2 A

C,A,B
I am Lyosha [343]3 years ago
3 0

Answer:

C,A,B

Explanation:

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if the coefficient of linear expansion of a metal is 2.05× 10^-6 k^-1 what will be its new length if 50cm metal went through a t
boyakko [2]

Answer:

L = L0 (1 + c T)   where c is the coefficient and T the change in temperature

L = 50 ( 1 + 2.05E-6 * 50) = 50.0051 cm

7 0
2 years ago
What is the frequency of radiation whose wavelength is 2.40 x 10-5 cm?
S_A_V [24]
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Angelina_Jolie [31]
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6 0
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Estimate the wavelength of electrons that have been accelerated from rest through a potential difference of 60 kV.
ivolga24 [154]

Answer: 2.068*10^{-14}m

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workdone= qV

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h= planck constant = 6.626*10^{-34}

c= speed of light =2.998* 10^{8}

v= potential difference= 6*10^{4}

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by making λ subject of formulae we have that

λ= \frac{hc}{qv}

λ = 6.626*10^{-34} * 2.998* 10^{8} / 1.602*10^{-16} * 6*10^{4}

λ = \frac{19.878*10^{-26} }{9.612*10^{-12} }

by doing the necessary calculations, we have that

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