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2 years ago

Which would be expected to have the higher boiling point, t-butyl alcohol (2-methyl-2-propanol) or n-butyl alcohol (1-butanol)?

1 answer:

3 0

I would imagine that n-butanol would have the higher boiling point because it has less branching and therefore stronger intermolecular forces between molecules.

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What happens when nitrogen fills its valence shell?

RSB [31]

Hello!

Like many other elements in chemistry, when an atom's valence shell is filled the element becomes stable. Through the octet rule we know that when the very last valence shell becomes filled, the atom is stable and therefore it is highly unlikely for the element to form bonds with that of another.

I hope this helped!

8 0

2 years ago

Ap chemistry how to determine if compound is ionic or molecular bqsed on formula

ludmilkaskok [199]

Ionic compound consists of a positively charged ion and a negatively charged anion. For example, NaCl. Na (sodium) is a cation (another word for positively charged ion) and Cl (chloride) is a anion (another way for negatively charged ion.)

Molecular compounds consists of only negatively charged ions. For example Br2I is a compound of 2 elements that are negatively charged.

Unlike ionic compounds, molecular compounds consists of two or more negatively charged elements.

7 0

2 years ago

Ethanol (c2h5oh) melts at -114Â°c. the enthalpy of fusion is 5.02 kj/mol. the specific heats of solid and liquid ethanol are 0.9

Nimfa-mama [501]

Answer: 4.18925 kJ heat is needed to convert 25.0 g of solid ethanol at -135 °C to liquid ethanol at -50°C.

Explanation:

Temperature of Solid $C_2H_5OH=-135^oC=138 K(0^oC=273K)$

Melting temperature of Solid $C_2H_5OH=114^oC=159 K$

Temperature of liquid $C_2H_5OH=-50^oC=223K$

Specific heats of solid ethanol = 0.97 J/gK

Specific heats of liquid ethanol = 2.3 J/gK

Heat required to melt the the 25 g solid $C_2H_5OH$ at 159 K

$\Delta T_1$ = 159 K - 138 K = 21 K

$Q_1=mc\Delta T= 25\times 0.97J/gK\times 21 K=509.25 J$

Heat required to melt and raise the temperature of $C_2H_5OH$ upto 223 K

$\Delta T_2$ = 223 K - 159 K = 64 K

$Q_2=mc\Delta T= 25\times 2.3J/gK\times 64 K=3680 J$

Total heat to convert solid ethanol to liquid ethanol at given temperature :

$Q_1+Q_2=509.25 J+3680 J=4189.25 J=4.18925 kJ$ (1kJ=1000J)

Hence, 4.18925 kJ of heat will be required to convert 25.0 g of solid ethanol at -135 °C to liquid ethanol at -50°C.

6 0

2 years ago

A pair of students determining the molarity of their unknown HCl solution calculates the concentration to be 0.0961 M on their f

Varvara68 [4.7K]

Answer:

Yes.

Explanation:

It should be noted that the meaning of molarity is the ratio of moles of solute per liter of solution.

It should be understood that when determining or finding the molarity of an unknown compound ,the process should be performed or carried out at least 3 times. This is done to remove any form of doubt.

The first calculated value for the concentration of the compound will be regarded as rough value, while the second and the third will be regarded as the first and second values respectively.

In this case, the third value for the concentration of HCl will be calculated to for confirmation of other value, that is to be finally sure of its concentration.

7 0

3 years ago

Read 2 more answers

A gas occupies a volume of 40.0 milliliters at 20 c if the volume is increased too 80.0 milliliters at constant pressure, the re

Troyanec [42]

Charles law gives the relationship between temperature and volume of gases. It states that the volume of gas is directly proportional to temperature at constant pressure.
V / T = k
where V - volume and T - temperature in Kelvin and k - constant
$\frac{V1}{T1} = \frac{V2}{T2}$
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - 20 °C + 273 = 293 K
substituting these values in the equation
$\frac{40.0 mL}{293 K} = \frac{80.0 mL}{T}$
T = 586 K
temperature in celsius = 586 K - 273 = 313 °C
new temperature is 313 °C

8 0

2 years ago