HELP ME PLEASE!

If for every action force an equal and opposite reaction force exists, how can anything ever be accelerated?

Anon25 [30]

The action and reaction forces act on different objects, therefore the net force is not always zero

Explanation:

Newton's third law of motion states that:

<em>"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"</em>

From the statement above, it is clear that the action and the reaction forces act on different objects. In fact, the action force acts on object B, while the reaction force acts on object A. This means that the two forces never appear in the same free-body diagram of the same object, and therefore when computing the net force acting on an object, we take into account only one of the two forces, never both.

For instance, imagine you are pushing a box along the floor with a force F (action). The box is exerting back on you a reaction force of equal magnitude in the opposite direction, - F. However, if we want to compute the net force on the box, we just take into account the action (F), not the reaction, because the reaction is acting on you, not on the box.

Therefore, the correct answer is

The action and reaction forces act on different objects, therefore the net force is not always zero

Learn more about Newton's third law:

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3 0

3 years ago

A box of books is in the floor. The following picture shows a push and a pull acting in the box.

nataly862011 [7]

Net force = 50 + 50 = 100 M
Since two forces act towards the same direction , total force should be their sum amd towards the same direction as the two forces

8 0

3 years ago

A spaceship travels toward the Earth at a speed of 0.97c. The occupants of the ship are standing with their torsos parallel to t

Ket [755]

Answer:

Explanation:

We shall apply length contraction einstein's relativistic formula to calculate the length observed by observer on the earth . For the observer , increased length will be observed for an observer on the earth

$L=\frac{.5}{\sqrt{1-(\frac{.97c}{c})^2 } }$

$L=\frac{.5}{.24}$

L= 2.05

The length will appear to be 2.05 m . and width will appear to be .5 m to the observer on the spaceship. . It is so because it is length which is moving parallel to the direction of travel. Width will remain unchanged.

3 0

4 years ago

Carbon and silicon are found in the earth's crust and in what type of bonds?

denis23 [38]

Trans metals and other non metals

5 0

3 years ago

What is the mechanical work done by the initial load placed on a fiber if the fiber is linearly deformed by 3 nm?

algol [13]

Answer:

$W=4.5\ k\times 10^{-18}\ J$

Explanation:

The mechanical work done by the load placed on a fiber if the fiber deforms by 3 nano-meter can be given in relation to the energy stored in a stretched fiber.

We know according to the Hooke's law within the elastic limit the stress is directly proportional to the strain. The constant introduced is called stiffness constant defined as the magnitude of load applied for the deformation of one unit in the dimension of the object.

<u>The energy stored in a stretched fiber is equal to the work done:</u>

$W=\frac{1}{2} k.\Delta x^2$

where:

k = stiffness constant

$\Delta x=$ deformation in the fiber = $3\times 10^{-9}\ m$

$W=4.5\ k\times 10^{-18}\ J$

5 0

3 years ago