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drek231 [11]
3 years ago
6

HELP ME PLEASE!

Physics
1 answer:
3241004551 [841]3 years ago
5 0

they have zero momentum before pushing off, is at least true

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Instruments in an airplane which is in level flight indicate that the velocity relative to the air (airspeed) is 180.00 km/h and
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Answer:

Explanation:

From the given information:

The coordinate axis is situated in the east and north direction.

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Similarly, the velocity of the plane in regard to the air in the coordinate system will be v_{P/A} = v( cos \theta \ i + sin \theta \ j)

where:

v_{P/A} = velocity of the plane in regard to the air

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replacing v = 180 km/ and θ = 20° in above equation, then:

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v_{P} = v_o( cos \phi \ i + sin \phi \ j)

where;

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Therefore, the velocity of the plane in the system is :

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v_A= ( 150 cos 30° - 180 cos 20°)i + ( 150 sin 30° - 180sin 20°)j

v_A= (-39.24 km/h)i + (13.44 km/h) j

The magnitude is:

v_A= (-39.24 km/h)i + (13.44 km/h) j

|v_A|^2 = \sqrt{ (-39.24 km/h)^2+ (13.44 km/h)^2}

v_A = 41.48 km/h

The airplane is moving at an angle of the inverse tangent to the abscissa and ordinate.

The angle of motion is:

tan θ = 39.24/13.44

tan θ = 2.9

θ  = tan ^{-1} (2.9)

θ  =  70.97°

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