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pickupchik [31]
3 years ago
12

A swimming pool, 20.0 m ? 12.5 m, is filled with water to a depth of 3.71 m. if the initial temperature of the water is 18.5°c,

how much heat must be added to the water to raise its temperature to 30.1°c? assume that the density of water is 1.000 g/ml.
Physics
1 answer:
Semenov [28]3 years ago
7 0
1askjjjohikjgnvrfntttkmvvvvvvvfdrtgfgfgfgffdxxsd

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HELP PLEASE !!
Umnica [9.8K]
If a car crashes into another car like this, the wreck should go nowhere. Besides this being an unrealistic question, the physics of it would look like this:

Momentum before and after the collision is conserved.

Momentum before the collision:
p = m * v = 50000kg * 24m/s + 55000kg * 0m/s = 50000kg * 24m/s
Momentum after the collision:
p = m * v = (50000kg + 55000kg) * v

Setting both momenta equal:
50000kg * 24m/s = (50000kg + 55000kg) * v

Solving for the velocity v:
v = 50000kg * 24m/s/(50000kg + 55000kg) = 11,43m/s

3 0
3 years ago
Two parallel plates that are initially uncharged are separated by 1.2 mm. What charge must be transferred from one plate to the
Gnoma [55]

Answer: 55.52 *10^-6 C= 55.52 μC

Explanation: In order to solve this question we have to take into account the following expressions:

potential energy stired in a capacitor is given by:

U=Q^2/(2*C)  where Q and C are the charge and capacitance of the capacitor.

then we have:

Q^2= 2*C*U=

C=εo*A/d where A and d are the area and separation of the parallel plates capacitor

Q^2=2*εo*A*U/d=2*8.85*10^-12*1.9*10^-5*11*10^3/(1.2*10^-3)=

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A 2,000 kg car is moving at 15m/s when it collides with a 1200kg car sitting still. Briefly compare the impulse imparted on the
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impulse = F × t

The greater the impulse exerted on something, the greater will be the change in momentum.

impulse = change in momentum

Ft = ∆(mv)

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International Disaster Management or FEMA
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A boy is exerting a force of 70 N at a 50-degree angle on a lawn mower. He is accelerating at 1.8 m/s2. Round the answers to the
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Answer:

are you in middle school

Explanation:

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