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3 years ago

Which statement about the density of warm water is most likely correct?

2 answers:

4 0

Option b. warm water is less dense than cold water.

It is due to the the effect of heat on water molecules that's why warm water tend to rise above cold ones. The molecules of the water are excited by the energy. They begin moving faster, so when they bump into one another, they bounce further away. The increase space between the fast-moving molecules decreases the density.

son4ous [18]3 years ago

3 0

Answer:

option b. warm water is less dense than cold water.

Explanation:

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Based on the chart, which food chain best models a flow of energy in this ecosystem?

GarryVolchara [31]

Answer:

Explanation:

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3 years ago

Los materiales sinteticos tienen implicaciones en el medio ambiente

svp [43]

Answer:

Explanation:

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3 years ago

(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of

Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

$P x V = k$

Therefore, for this problem the step by step explanation is:

$P_{1} xV_{1} = P_{2} xV_{2}$

Clearing P2 and replacing

$P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm$

7 0

3 years ago

What is the element that is in period 5 and group 3?

rjkz [21]

Answer:

Rubidium

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6 0

3 years ago

How much energy, in joules, does 150.0 g of water with an initial temperature of 25 C need to absorb be raised to a final temper

satela [25.4K]

Answer:

31395 J

Explanation:

Given data:

mass of water = 150 g

Initial temperature = 25 °C

Final temperature = 75 °C

Energy absorbed = ?

Solution:

Formula:

q = m . c . ΔT

we know that specific heat of water is 4.186 J/g.°C

ΔT = final temperature - initial temperature

ΔT = 75 °C - 25 °C

ΔT = 50 °C

now we will put the values in formula

q = m . c . ΔT

q = 150 g × 4.186 J/g.°C × 50 °C

q = 31395 J

so, 150 g of water need to absorb 31395 J of energy to raise the temperature from 25°C to 75 °C .

5 0

3 years ago