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VashaNatasha [74]
3 years ago
10

PLEASE HELP is this a chemical or physical change???

Chemistry
2 answers:
tekilochka [14]3 years ago
8 0
Chemical change! answer: chemical change!

step by step explanation:
skad [1K]3 years ago
5 0

Answer:

Chemical, cause physical are changes affecting the form of a chemical substance, but not its chemical composition. This doesn't affect the substance but the composition.

Explanation:

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Use this diagram to answer the following
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4 0
3 years ago
For the hypothetical reaction: A + B ---> 2C, write an expression that relates the disappearance of A and B to the appearance
forsale [732]

Answer:

Rate expression has been given below

Explanation:

According to the given equation, 1 molecule of A reacts with 1 molecule of B and produces 2 molecules of B at a time.

So, rate of disappearance of both A and B are one half of rate of appearance of B

Hence rate expression can be represented as:

Rate=\frac{-\Delta [A]}{\Delta t}=\frac{-\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}

where \frac{-\Delta [A]}{\Delta t} is rate of disappearance of A, \frac{-\Delta [B]}{\Delta t} is rate of disappearance of B and \frac{\Delta [C]}{\Delta t} rate of appearance of C

8 0
3 years ago
What is the half-life of A? What will the pressure, initially 32.1 kPa, at
kodGreya [7K]

Answer:

a) 32.09 kPa

b) 32.09 kPa

Explanation:

Given data:

rate constant = 3.56\times 10^{-7} s^{-1}

initial pressure is = 32.1 kPa

half life of A is calculated as

t_{1/2} = \frac{ln 2}{k}

t_{1/2} = \frac{ln 2}{3.56\time 10^{-7}}

t_{1/2} = = 1.956 \times 10^6 s

for calculating pressure we have follwing expression

ln p = ln P_o - kt

P =P_o e^{-kt}

a) P = 32.1 e^{-3.56\times 10^{-7} \times 10} = 32.09 kPa

b) P = 32.1 e^{-3.56\times 10^{-7} \times 10\times 60} = 32.09 kPa

5 0
3 years ago
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