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VashaNatasha [74]
3 years ago
10

PLEASE HELP is this a chemical or physical change???

Chemistry
2 answers:
tekilochka [14]3 years ago
8 0
Chemical change! answer: chemical change!

step by step explanation:
skad [1K]3 years ago
5 0

Answer:

Chemical, cause physical are changes affecting the form of a chemical substance, but not its chemical composition. This doesn't affect the substance but the composition.

Explanation:

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What is the main difference between protons and neutrons?
Lorico [155]

Answer:

Protons have a much larger volume than neutrons.

Explanation:

Protons have a slightly smaller mass than neutrons.

Protons have a positive charge.

Protons and neutrons make up the nucleus.

8 0
3 years ago
the speed limit is posted as 35 km/hr . your speedometer reads that you are going 40 miles/hr. are you speeding?
Morgarella [4.7K]
No, because 40 miles is the same as nearly 25 km/h. 
4 0
3 years ago
A sample of 211 g of iron (III) bromide is reacted with
Alisiya [41]

FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

  • FeBr₃

211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :

\tt n=\dfrac{mass}{MW}\\\\n=\dfrac{211}{295,56}\\\\n=0.714

  • Na₂S

186 g of Sodium sulfide(MW=78,0452 g/mol), so mol Na₂S :

\tt n=\dfrac{186}{78.0452}=2.38

Coefficient ratio from the equation FeBr₃ :  Na₂S = 2 : 3, so mol ratio :

\tt FeBr_3\div Na_2S=\dfrac{0.714}{2}\div \dfrac{2.38}{3}=0.357\div 0.793

So  FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

\tt \dfrac{6}{3}\times 0.714=1.428

6 0
3 years ago
The pka of hf is 3.2 determine the pkb of hf?
Julli [10]

Well, first we must remember that

pK_{a}+pK_{b}=14

This is because

K_{a}*K_{b}=10^{-14}

-log(K_{a}*K_{b})=-log(10^{-14})\\-logK_{a}+-logK_{b}=-log(10^{-14})\\pK_{a}+pK_{b}=14

So then

pK_{b}=14-pK_{a}=14-3.2=1.8

7 0
4 years ago
Read 2 more answers
A sample of gas with a volume of 30.0 ml at 25.0c is heated to 50.0c what is the new volume of the gas
garik1379 [7]

Answer:

The new volume is 60ml

Explanation

using the equation p1v1/n1t1=p2v2/n2t2 we would divied 30 by 25 the multiply by 50 to get 60

7 0
2 years ago
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