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ss7ja [257]
4 years ago
8

Please need help (ASAP ) with 1.and 3.(Need) please will give you Brainliest

Mathematics
1 answer:
kolbaska11 [484]4 years ago
7 0

I believe the answer to 1 is congruent complements theorem. The theorem states, if two angles are complementary to the same angle, then they are congruent. That theorem fits this situation.

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Which of the following statements about the function cannot be used to conclude that is defined at x = 1?
Murljashka [212]
A Lin x —>1 f(x) exists
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4 years ago
David and Mark are marking exam papers. Each set takes David 24 minutes and Mark 1 hour. Express the times David and Mark take a
attashe74 [19]

Answer:

2:5

Step-by-step explanation:

david=24mins

mark = 1hour

change 1 hour to mins

DAVID=24

MARK=60

24:60

THEN SIMPLIFY

24/60

<em>=</em><em>2</em><em>/</em><em>5</em>

<em><u>2</u></em><em><u>:</u></em><em><u>5</u></em>

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4 years ago
For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?
irakobra [83]

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is \frac{2x^2+8x}{(x+4)(x^2-9)}

To find for what value of x is undefined in the given expression :

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}

=\frac{2x}{x^2-9}

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}

If we put x=3 in the above expression we get

\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}

=\frac{6}{9-9}

=\frac{6}{0}

Therefore \frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}

The value at x =3 is undefined for the given expression

7 0
4 years ago
Determine the domain and range of the following
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Answer:

Domain: (-3,-2,0,1,2,3)

Range: (9,4,1,0,1,4,9)

Step-by-step explanation:

5 0
4 years ago
Find the missing number.<br> 7 × <br> = 21
dalvyx [7]

Answer:

7x3=21

Step-by-step explanation:

pls mark Brainliest :)

3 0
4 years ago
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