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Alexxandr [17]
3 years ago
10

An AC source with an output rms voltage of 27.0 V at a frequency of 60.0 Hz is connected across a 12.2-µF capacitor. (a) Find th

e capacitive reactance. Ω (b) Find the rms current. A (c) Find the maximum current in the circuit. A (d) Does the capacitor have its maximum charge when the current has its maximum value? Yes No Explain. This answer has not been graded yet.
Physics
1 answer:
gulaghasi [49]3 years ago
6 0

Answer:

Explanation:

a) capacitive reactance Xc = 1/2πfC

f is the frequency of the AC source

C is the capacitance of thw capacitor

Given f = 60.0Hz

C = 12.2-µF

C = 12.2 × 10^-6Farads

Xc = 1/2π×60×12.2×10^-6

Xc = 1/0.004599

Xc = 217.44ohms

b) Using the formula Vrms = IrmsXc Vrms

Irms = Vrms/Xc

Irms = 27.0/217.44

Irms = 0.124Amperes

c) Since Irms = Im/√2

Where Im is the maximum current

Im = Irms×√2

Im = 0.124× √2

Im = 0.088A

d) No, the capacitor has no charge when the current is at maximum.

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4200 N  is the tension in the cable that pulls the elevator upwards.

The correct option is A.

<h3>What does tension ?</h3>

Tension is the force that is sent through a rope, thread, or wire whenever two opposing forces pull on it. Along the whole length of the wire, the tensile stress pulls equally on all objects at the ends. Every physical object that comes into contact with that other one exerts force on it.

<h3>Briefing:</h3>

We employ the following formula to determine the cable's tension.

Formula:

T = mg+ma............ Equation 1

Where:

T is the cable's tension.

M = Mass of the elevator and the Joey

Accelerating with a

g = Gravitational acceleration

Considering the query,

Given:

m = (300+60) = 360 kg

a = 2 m/s²

g = 9.8 m/s²

Substitute these values into equation 2

T = (360×9.8)+(360×2)

T = 3528+720

T = 4248 N

T ≈ 4200 to the nearest hundred.

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1 year ago
A roller coaster goes from 10 m/s to 30 m/s in 5 seconds. What is it's acceleration? <br> Vf-Vi/T
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Explain the term "avalanche state"
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Answer:

The downwind side of an obstacle such as a ridge. The addition of weight on top of a snowpack, usually from precipitation, wind drifting, or a person. An avalanche that releases from a point and spreads downhill collecting more snow - different from a slab avalanche. Also called a point-release or sluff.

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Answer:

9.773m/s2

Explanation:

Given,

h=8848m

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So,

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g′=g(1−h2h)

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=9.8(1−0.00276)

9.8×0.99724

=9.773m/s2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s2

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