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olasank [31]
3 years ago
11

If you climb to the top of Mt. Everest, you will be 8850 m (about 5.50 mi) above sea level.

Physics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

9.773m/s2

Explanation:

Given,

h=8848m

The value of sea level is 9.08m/s2

So,

Let g′ be the acceleration due to the gravity on the Mount Everest.

g′=g(1−h2h)

=9.8(1−640000017696)

=9.8(1−0.00276)

9.8×0.99724

=9.773m/s2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s2

Hope it helped!!!

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A battery charger is connected to a dead battery and delivers a current of 8.9 A for 4.7 hours, keeping the voltage across the b
adell [148]

Answer:

1807.56 kJ

Explanation:

Parameters given:

Current, I = 8.9A

Time, t = 4.7hrs = 4.7 * 3600 = 16920 secs

Voltage, V = 12V

Electrical energy is given as:

E = I*V*t

Where I = Current

V = Voltage/Potential differenxe

t = time in seconds.

E = 8.9 * 12 * 16920

E = 1807056 J = 1807.056 kJ

3 0
3 years ago
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Light travels 300,000,000m/sec, and one year has approximately 32,000,000 seconds. A light year is the distance light travels in
dem82 [27]
A) 3 x 10 ^ 8
b) 3 x 10 ^ 5
c) 3.2 x 10 ^ 7
d) 9.6 x 10 ^ 15 m
e) 9.6 x 10 ^ 17 cm
3 0
3 years ago
A current cannot produce a magnetic field. *<br><br> True or false
GalinKa [24]

Answer:

False

Explanation:

False, as a magnetic field is generated whenever current travels through a conductor.

An electromagnet consists of a coil of wire wrapped around a bar of iron. The coil and iron bar get magnetized when electric current flows through the wire. An electromagnet also has north and south magnetic poles. The magnetic field is strongest at either pole of the magnet.

8 0
3 years ago
When a 10 V battery is connected to a resistor, 5 A of current flows through the resistor. What is the resistor's value?
SashulF [63]

Given data

*The value of battery voltage is V = 10 V

*The current flows through the resistor is I = 5 A

The formula for the resistor is given by the Ohm's law as

R=\frac{V}{I}

Substitute the values in the above expression as

\begin{gathered} R=\frac{10}{5} \\ =2\text{ ohm} \end{gathered}

7 0
1 year ago
Josh did an experiment recording the changes in temperature in sand and water when exposed to a light source, and then when the
Marrrta [24]

Before going to solve this question first we have to understand specific heat capacity of a substance .

The specific heat of a substance is defined as amount of heat required to raise the temperature of 1 gram of substance through one degree Celsius. Let us consider a substance whose mass is m.Let Q amount of heat is given to it as a result of which its temperature is raised  from T to T'.

Hence specific heat  of a substance is calculated as-

                                              c= \frac{Q}{m[T'-T]}

Here c is the specific heat capacity.

The substance whose specific heat capacity is more will take more time to be heated up to a certain temperature as compared to a substance having low specific heat which is to be heated up to the same temperature.

As per the question John is experimenting on sand and water.Between sand and water,water has the specific heat 1 cal/gram per degree centigrade which is larger as compared to sand.Hence sand will be heated faster as compared to water.The substance which is heated faster will also cools faster.

From this experiment John concludes that water has more specific heat as compared to sand.

7 0
3 years ago
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