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4 years ago

What is the net ionic equation for ammonia and phosphoric acid?

Chemistry

1 answer:

olganol [36]4 years ago

7 0

N<span>et ionic equation for ammonia and phosphoric acid</span> is
3 NH4OH + H3PO4 >> (NH4)3PO4 + 3 H2O
hope this helps

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I think what '13C' means is the isotope of carbon with mass number of 13. Its mass is 13 amu. The unit amu is equivalent to g/mol. The average atomic mass of Carbon is actually 12. But since we are solving for this particular isotope, we use a molar mass of 13 g/mol.

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Answer: The molecular formula will be $C_8N_4H_{10}O_2$

Explanation:

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Mass of N = 28.85 g

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Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{49.47g}{12g/mole}=4.12moles$

Moles of N = $\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{28.85g}{14g/mole}=2.06moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{16.48g}{16g/mole}=1.03moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.20g}{1g/mole}=5.20moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{4.12}{1.03}=4$

For N = $\frac{2.06}{1.03}=2$

For O = $\frac{1.03}{1.03}=1$

For H = $\frac{5.20}{1.03}=5$

The ratio of C : N: O: H = 4: 2: 1: 5

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The empirical weight of $C_4N_2OH_5$ = 4(12)+2(14)+1(16)+5(1)= 97 g.

The molecular weight = 194.19 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{194.19}{97}=2$

The molecular formula will be = $2\times C_4N_2H_5O=C_8N_4H_{10}O_2$

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