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borishaifa [10]
4 years ago
12

Pertaining to simple machines and levers what changes when the fulcrum position is modified

Physics
1 answer:
ladessa [460]4 years ago
6 0

Explanation :

Simple machines makes our work easier. Lever is one of the simple machine which consists of rigid rod that is pivoted at a fixed support called as Fulcrum.

There are three classes of lever.

Class 1 : In this type of class, fulcrum is placed in between effort and load. Hence the movement of load is in reverse direction of the movement of effort. (fig 1)

Class 2 : In this type of, the load is between the effort and the fulcrum. Hence, the movement of load is in same direction as that of the effort. (fig 2)

Class 3 : In this type of lever the effort between the load and the fulcrum. Hence, both the effort and load are in same direction. (fig 3)

Hence, when the position of fulcrum is modified the effort force changes.

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A standard gold bar stored at Fort Knox, Kentucky, is 7.00 inches long, 3.63 inches wide, and 1.75 inches tall. Gold has a densi
Liula [17]

Answer:

14.1 kg

Explanation:

Given:

Length=7.00inches

Width=3.63 inches

Height=1.75 inches

density = 19,300 kg/m3.

We can convert the given parameters to metre for unit consistency

But we know 1 inches= 0.0254 metre

✓Then Length l=7.00inches

=7×0.0254 metre=0.1778m

✓Width w =3.63 inches

==3.63 ×0.0254 metre=0.092m

✓Height h =1.75 inches

=1.75 ×0.0254 metre=0.0445 m

But Mass= density × volume

Volume= Length× width×height

Mass= density× Length× width×height

= 19300kg/m³×0.1778×0.0922×0.0445

=14.1 kg

Therefore, the mass of the gold bar is 14.1 kg

4 0
3 years ago
Potential energy is the ability to:
Ymorist [56]

Answer:

potential energy is the ability to do work

8 0
4 years ago
Consider two blocks of copper. Block A contains 800 atoms and initially has a total of 20 quanta of energy. Block B contains 200
marishachu [46]

Answer:

Option B and Option D are true

Explanation:

We are given;

Number of atoms in block A = 800

Energy content in block A = 20 quanta

Number of atoms in block B = 200

Energy content in block B = 80 quanta

The energy of a system which is an extensive quantity,depends on the mass or number of moles of the system. However, at equilibrium, the energy density of the two copper blocks will be equal. That is, each atom of Cu in the two blocks will, on average, have the same energy. Because block A has 4 times more atoms than block B, it will have 4 times more quanta of energy. Thus, option B is therefore true while option A is false.

Temperature is a measure of the average kinetic energy of the atoms in a material. Now, if each atom in blocks A and B have the same average energy, then the temperatures of blocks A and B will be equal at equilibrium. Thus, option D is true.

Entropy of a system is an extensive quantity that depends on the the mass or number of atoms in the system. Because block A is bigger than block B, it will have higher entropy. However, that the specific entropy (the entropy per mole or per unit mass) is an intensive quantity -- it is independent of the size of a system. The molar entropy of blocks A and B are equal at equilibrium. Thus option C is false.

8 0
3 years ago
What is meant by pressure?write its unit.
Mars2501 [29]

Answer:

Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed

Unit: Pascal (Pa)

1Pa = 1N/m^2

5 0
3 years ago
How much heat is necessary to change 350 g of ice at -20 degrees Celsius to water at 20 Celsius?
sergejj [24]

Answer:

160790 J

Explanation:

We can find the heat necessary for the ice to go from -20 degrees Celsius to 0 degrees Celsius:

Q=mc\Delta t

Where c=2.09 J/g^{\circ}C is the specific heat of ice, that is the amount of heat that must be supplied per unit mass to raise its temperature in a unit.

Q=(350g)(2.09 J/g^{\circ}C)(0^{\circ}C-(-20^{\circ}C))=14630 J

We must calculate the latent heat of fusion required for this ice mass to change to water:

Q=mH

Where H=334 J/g is the specific latent heat of fusion of water, that is the amount of energy needed per unit mass of a substance at its melting point to change from the solid to the liquid state.

Q=(350g)(334 J/g)=116900 J

Then we calculate the heat necessary for the water to go from 0 degrees Celsius to 20 degrees Celsius:

Q=mc\Delta t

Where c=4.18 J/g^{\circ}C is the specific heat of water, that is the amount of heat that must be supplied per unit mass to raise its temperature in a unit.

Q=(350g)(4.18 J/g^{\circ}C)(20^{\circ}C-0^{\circ}C)=29260 J

Finally the 3 results are added:

Q_{T}=14630 J + 116900 J + 29260 J=160790 J

6 0
3 years ago
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