Mass=1.01 kg; volume =1000cm3

Tatiana [17]

Answer:

vdsfdvdsfdsf

Explanation:

https://newsengin.zendesk.com/hc/vew/community/posts/360056216292-%D9%85%D9%88%D9%82%D8%B9-%D8%A7%D9%84%D9%86%D9%88%D8%B1-%D9%85%D8%B3%D9%84%D8%B3%D9%84-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D8%A7%D9%84%D8%AB%D8%A7%D9%85%D9%86%D8%A9-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9-%D9%82%D9%8A%D8%A7%D9%85%D8%A9-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9

https://newsengin.zendesk.com/hc/pst/community/posts/360056216252-Serial-TV-%D9%85%D8%B3%D9%84%D8%B3%D9%84-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-7-%D8%A7%D9%84%D8%B3%D8%A7%D8%A8%D8%B9%D8%A9-%D8%A7%D9%88%D9%86%D9%84%D8%A7%D9%8A%D9%86-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-7-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9-HD

https://newsengin.zendesk.com/hc/vew/community/posts/360056216292-%D9%85%D9%88%D9%82%D8%B9-%D8%A7%D9%84%D9%86%D9%88%D8%B1-%D9%85%D8%B3%D9%84%D8%B3%D9%84-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D8%A7%D9%84%D8%AB%D8%A7%D9%85%D9%86%D8%A9-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9-%D9%82%D9%8A%D8%A7%D9%85%D8%A9-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9

4 0

3 years ago

The proton has a mass of?

aliina [53]

The relative mass is 1

3 0

3 years ago

PRACTICE

Stels [109]

Answer:

35.8 u

Explanation:

The atomic mass of Cl is the weighted average of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its percent abundance).

Atomic mass of Cl-35 = 17p + 18n = 17 × 1.007 u + 18 × 1.009 u

= 17.119 u + 18.162 u = 35.28 u

Atomic mass of Cl-37 = 17p + 20n = 17 × 1.007 u + 20 × 1.009 u

= 17.119 u + 20.180 u = 37.30 u

Set up a table for easy calculation.

0.755 × 35.28 u = 26.64 u

0.245 × 37.30 u = 9.138 u

TOTAL = 35.8 u

Note: The actual atomic mass of Cl is 35.45 u.

The calculated value above is incorrect because

(a) the given isotopic percentages are incorrect and

(b) the protons and neutrons have less mass when they are in the nucleus than when they are free. Thus, the calculated masses of Cl-35 and Cl-37 are too high.

7 0

4 years ago

Read 2 more answers

Momentum is. __________

horrorfan [7]

is the product of the mass and velocity of an object, quantified in kilogram-meters per second.

7 0

3 years ago

C3H8 combusts.

Nina [5.8K]

Answer:

The balanced chemical equation:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)

Explanation:

(a): The balanced chemical equation:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)

(b): Determine moles of each reactant:

(5.34 g C3H8) × (1 mol C3H8 / 44.11 g C3H8) = 0.1211 mol C3H8

(25.2 g O2) × (1 mol O2 / 32.00 g O2) = 0.7875 mol O2

According to the chemical equation above: n(C3H8) = n(O2)/5

Choose one reactant and determine how many moles of the other reactant are necessary to completely react with it. Let's choose C3H8:

n(O2) = 5 × n(C3H8) = 5 × 0.1211 mol = 0.6055 mol

The calculation above means that we need 0.6055 mol of O2 to completely react with 0.1211 mol C3H8.

We have 0.7875 mol O2 and therefore more than enough oxygen.

Thus oxygen (O2) is in excess and tricarbon octahydride (C3H8) must be the limiting reactant.

The limiting reactant is tricarbon octahydride (C3H8).

(c):

(5.34 g C3H8) × (1 mol C3H8 / 44.11 g C3H8) × (4 mol H2O/ 1 mol C3H8) × (18.02 g H2O / 1 mol H2O) = 8.726 g H2O

8.726 grams of water (H2O) is produced.

(d):

0.7875 mol O2 - 0.6055 mol of O2 = 0.182 mol O2 (excess O2)

(0.182 mol O2) × (1 mol O2 / 32.00 g O2) = 5.824 g O2

5.824 grams of oxygen gas (O2) is left over after the reaction is complete.

(e):

%H2O = (6.98 g / 8.726 g) × 100% = 79.99% = 80.00%

The percent yield of water (H2O) is 80.00%.

4 0

3 years ago