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Law Incorporation [45]
3 years ago
5

There are 3 different possible isomers of a dibromoethene molecule. what are these isomers?

Chemistry
1 answer:
olasank [31]3 years ago
6 0

Answer:

1,1-, (Z)-1,2-, and (E)-1,2-dibromoethene

Explanation:

Their structures are shown below.

The 1,2-dibromoethenes (2 and 3) are positional isomers

of 1,1-dibromoethene (1).

(Z)-1,2-dibromoethene (2) and (E)-1,2-dibromoethene (3) are stereoisomers (geometric isomers) of each other.

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Why are alkalis sometimes<br> described as the opposite of<br> acids?
zlopas [31]

Answer: Because Alkalis are bases that can dissolve in water, which can also neutralize acid.

7 0
3 years ago
Given this reaction, N2O4(g) 2NO2(g), what shifts will occur if Q = K?
MAXImum [283]

Answer:

It shifts to the left

Explanation:

7 0
3 years ago
An element forms an oxide, E₂O₃, and a fluoride, EF₃.(a) Of which two groups might E be a member?
Fittoniya [83]

a) The E might belong to group 13.

As the formula of a chemical compound is derived by the cross multiplication of the valency of the atoms. As formula of the given oxide is  and valency of O atom is -2, therefore valency of element E must be +3 in order to obtain E2O3.

Also, in EF3, the valency of E will be +3 because there are three atoms of fluorine who has an individual valency of -1. Thus, e will have the valency of +3.

The Group 13 is the boron group which has the following elements:

  • Boron
  • Aluminium
  • Gallium
  • Indium
  • Thallium

All these elements have the valency of +3.

To know more about Valency, refer to this link:

brainly.com/question/12717954

#SPJ4

8 0
2 years ago
A 5.024 mg sample of an unknown organic molecule containing carbon, hydrogen, and nitrogen only was burned and yielded 13.90 mg
Dafna1 [17]

Answer:

C8H17N

Explanation:

Mass of the unknown compound = 5.024 mg

Mass of CO2 = 13.90 mg

Mass of H2O = 6.048 mg

Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:

For carbon, C:

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 13.90 = 3.791 mg

For hydrogen, H:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H = 2/18 x 6.048 = 0.672 mg

For nitrogen, N:

Mass N = mass of unknown – (mass of C + mass of H)

Mass of N = 5.024 – (3.791 + 0.672)

Mass of N = 0.561 mg

Now, we can obtain the empirical formula for the compound as follow:

C = 3.791 mg

H = 0.672 mg

N = 0.561 mg

Divide each by their molar mass

C = 3.791 / 12 = 0.316

H = 0.672 / 1 = 0.672

N = 0.561 / 14 = 0.040

Divide by the smallest

C = 0.316 / 0.04 = 8

H = 0.672 / 0.04 = 17

N = 0.040 / 0.04 = 1

Therefore, the empirical formula for the compound is C8H17N

8 0
3 years ago
Please Help! It's a little bit urgent but Thank you for the help!
RideAnS [48]

answer is compound i think

Explanation:

6 0
3 years ago
Read 2 more answers
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