It's still 20 kg. Mass doesn't change according to gravity, only weight changes.
Answer:
h = 13.06 m
Explanation:
Given:
- Specific gravity of gasoline S.G = 0.739
- Density of water p_w = 997 kg/m^3
- The atmosphere pressure P_o = 101.325 KPa
- The change in height of the liquid is h m
Find:
How high would the level be in a gasoline barometer at normal atmospheric pressure?
Solution:
- When we consider a barometer setup. We dip the open mouth of an inverted test tube into a pool of fluid. Due to the pressure acting on the free surface of the pool, the fluid starts to rise into the test-tube to a height h.
- The relation with the pressure acting on the free surface and the height to which the fluid travels depends on the density of the fluid and gravitational acceleration as follows:
P = S.G*p_w*g*h
Where, h = P / S.G*p_w*g
- Input the values given:
h = 101.325 KPa / 0.739*9.81*997
h = 13.06 m
- Hence, the gasoline will rise up to the height of 13.06 m under normal atmospheric conditions at sea level.
Answer: A light bulb can be all of the following except option C (a consumer product if it is used to light the office of the board of directors.)
Explanation:
Products are classified as being BUSINESS or CONSUMER products according to the buyer's intended use of the product.
-Consumer products: these are sold goods that are used for personal, family, or household use. The intention of the buyer is for the products to satisfy his personal needs and desires. Example of some of the consumer products include: toothpaste, eatables and clothes.
Business products: products that are not for personal use but for the manufacturing of other goods are called business products.
Therefore a bulb is not serving as a personal use when used to light the office of the board of directors rather it's serving as a business product .
Light can't reflect off them I think
Answer:
0.0006091222 m
Explanation:
q = Charge = 42 pC
V = Voltage = 620 V
= Permittivity of free space =
Electric potential is given by (at r = R)
The radius of the drop is 0.0006091222 m