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STALIN [3.7K]
3 years ago
6

While passing through a human cell, an x-ray photon interacts with and inactivates the cell’s master molecule. What is the conse

quence for the cell?
Physics
1 answer:
Yuliya22 [10]3 years ago
3 0

Answer:

Cell Death

Explanation:

Cell death is defined as the biological process which ceases the function of the cell to carry out. This can be caused due to the formation of new cells in place of old cells.

Or it can be cause due to some serious disease or may be caused due to the injury or due to the death of that organism to which these cells belong.

And another case is that when X-ray photon interact with the human cell while it passes through the cell, it   will damage the cell and cease it to function well and a more drastic condition occurs and that cell become dead.  

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Starting from rest, a racecar moves 112 m in the first 7 s of uniform acceleration. What is the car's acceleration?​
Leviafan [203]

Answer:

215mph

Explanation:

multiply 112milws by 2 and multiple that by seven, then divide it by two

6 0
2 years ago
(Please Help, Will Give BRAINLIEST Answer)
Xelga [282]

Answer:

A

Explanation:

Initial gravitational energy = final kinetic energy + heat

mgh = KE + Q

(50 kg) (9.81 m/s²) h = 78400 J + 884000 J

h = 1960 meters

4 0
3 years ago
You are traveling in a car toward a hill at a speed of 36.4 mph. The car's horn emits sound waves of frequency 231 Hz, which mov
Marina CMI [18]

Answer:

<em>a. The frequency with which the waves strike the hill is 242.61 Hz</em>

<em>b. The frequency of the reflected sound wave is 254.23 Hz</em>

<em>c. The beat frequency produced by the direct and reflected sound is  </em>

<em>    11.62 Hz</em>

Explanation:

Part A

The car is the source of our sound, and the frequency of the sound wave it emits is given as 231 Hz. The speed of sound given can be used to determine the other frequencies, as expressed below;

f_{1} = f[\frac{v_{s} }{v_{s} -v} ] ..............................1

where f_{1} is the frequency of the wave as it strikes the hill;

f is the frequency of the produced by the horn of the car = 231 Hz;

v_{s} is the speed of sound = 340 m/s;

v is the speed of the car = 36.4 mph

Converting the speed of the car from mph to m/s we have ;

hint (1 mile = 1609 m, 1 hr = 3600 secs)

v = 36.4 mph *\frac{1609 m}{1 mile} *\frac{1 hr}{3600 secs}

v = 16.27 m/s

Substituting into equation 1 we have

f_{1} =  231 Hz (\frac{340 m/s}{340 m/s - 16.27 m/s})

f_{1}  = 242.61 Hz.

Therefore, the frequency which the wave strikes the hill is 242.61 Hz.

Part B

At this point, the hill is the stationary point while the driver is the observer moving towards the hill that is stationary. The frequency of the sound waves reflecting the driver can be obtained using equation 2;

f_{2} = f_{1} [\frac{v_{s}+v }{v_{s} } ]

where f_{2} is the frequency of the reflected sound;

f_{1}  is the frequency which the wave strikes the hill = 242.61 Hz;

v_{s} is the speed of sound = 340 m/s;

v is the speed of the car = 16.27 m/s.

Substituting our values into equation 1 we have;

f_{2} = 242.61 Hz [\frac{340 m/s+16.27 m/s }{340 m/s } ]

f_{2}  = 254.23 Hz.

Therefore, the frequency of the reflected sound is 254.23 Hz.

Part C

The beat frequency is the change in frequency between the frequency of the direct sound  and the reflected sound. This can be obtained as follows;

Δf = f_{2} -  f_{1}  

The parameters as specified in Part A and B;

Δf = 254.23 Hz - 242.61 Hz

Δf  = 11.62 Hz

Therefore the beat frequency produced by the direct and reflected sound is 11.62 Hz

3 0
3 years ago
A pulley with a radius of 3.0 cm and a rotational inertia of 4.5 x 10^-3 kg∙m2 is suspended from the ceiling. A rope passes over
solmaris [256]

Answer:

maximum kinetic energy is for Pulley

e) The pulley

Explanation:

Let 4 kg block is moving downwards with speed "v" so we can say that 2 kg block will move upwards with same speed "v"

Now we know that pulling is in pure rotational motion

so we will have

\omega = \frac{v}{R}

\omega = \frac{v}{0.03}

now kinetic energy of each is given as

For 4 kg block

K_1 = \frac{1}{2}(4)(v^2) = 2v^2

for 2 kg block

K_2 = \frac{1}{2}(2)(v^2) = v^2

For pulley

K_3 = \frac{1}{2}I\omega^2

K_3 = \frac{1}{2}(4.5\times 10^{-3})\frac{(v^2)}{0.03^2}

K_3 = 2.5 v^2

So maximum kinetic energy is for Pulley

3 0
3 years ago
Why are convection currents; why are they hotter and colder parts of earth
Dafna1 [17]
This current causes earth quakes that makes a river,pond,or a lake
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7 0
3 years ago
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