Question

Find the density of seawater at a depth where the pressure is 680 atm if the density at the surface is 1030 kg/m3. Seawater has a bulk modulus of 2.3 × 109 N/m2. Bulk modulus is defined to be
B ≡ rho0 ∆P ∆rhoAnswer in units of kg/m3.

Answer 1

Answer:

$1060.41kg/m^3$

Explanation:

Bulk modulus is defined as the relative change in the volume of a body produced by a unit of compressive acting uniformly over its surface:

$B=\rho _o \frac{\bigtriangleup P }{\bigtriangleup \rho}$

Hence the density of the seawater at a depth of 680atm is calculated as:-

$\rho=\rho_o +\bigtriangleup \rho=\rho_o(1+\frac{\bigtriangleup P}{B})\\\\=1030 \times (1+ \frac{(680-1)\times10^5}{2.3\times 10^9})\\=1060.41kg/m^3$