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kompoz [17]
3 years ago
9

1. What is scratch programming?2. What is a sprite?

Computers and Technology
1 answer:
JulsSmile [24]3 years ago
3 0
1. The answer to the question what is scratch programming is a language and an online community where children can program and share interactive media

2. The answer to the question what is a sprite is a two dimensional bitmap that is intergrated into a larger scence.

Hope this helps
If you don't understand plz message me
If you do plz brainlest me
If you need help with any other tecnology questions you can also message me for that too.
Thank you and have a wonderful day!!!
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Note: You can use a word document to write your answers and copy-paste your answer to the area specified. a. (5 points) Convert
MrMuchimi

Answer:

EA9_{16} = 3753

CB2_{16} = 3250

(1011 1110 1101 1011 1010)_2 = 781754

(1010 1000 1011 1000 1110 1101)_2 = 11057389

(1011 1110 1101 1011 1010)_2 = BEDBA

(1010 1000 1011 1000 1110 1101)_2 =  A8B8ED

74510_8= 221416

67210_8 = 203212

Explanation:

Solving (a): To base 10

(i)\ EA9_{16

We simply multiply each digit by a base of 16 to the power of their position.

i.e.

EA9_{16} = E * 16^2 + A * 16^1 + 9 * 16^0

EA9_{16} = E * 256 + A * 16 + 9 * 1

In hexadecimal

A = 10; E = 14

So:

EA9_{16} = 14 * 256 + 10 * 16 + 9 * 1

EA9_{16} = 3753

(ii)\ CB2_{16}

This gives:

CB2_{16} = C * 16^2 + B * 16^1 + 2 * 16^0

CB2_{16} = C * 256 + B * 16 + 2 * 1

In hexadecimal

C = 12; B =11

So:

CB2_{16} = 12 * 256 + 11 * 16 + 2 * 1

CB2_{16} = 3250

Solving (b): To base 10

(i)\ (1011 1110 1101 1011 1010)_2

We simply multiply each digit by a base of 2 to the power of their position.

i.e.

(1011 1110 1101 1011 1010)_2 = 1 * 2^{19} + 0 * 2^{18} + 1 * 2^{17} + 1 * 2^{16} +1 * 2^{15} + 1 * 2^{14} + 1 * 2^{13} + 0 * 2^{12} + 1 * 2^{11} + 1 * 2^{10} + 0 * 2^9 + 1 * 2^8 +1 * 2^7 + 0 * 2^6 + 1 * 2^5 + 1 * 2^4 + 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 0 * 2^0

(1011 1110 1101 1011 1010)_2 = 781754

(ii)\ (1010 1000 1011 1000 1110 1101)_2

(1010 1000 1011 1000 1110 1101)_2 = 1 * 2^{23} + 0 * 2^{22} + 1 * 2^{21} + 0 * 2^{20} +1 * 2^{19} + 0 * 2^{18} + 0 * 2^{17} + 0 * 2^{16} + 1 * 2^{15} + 0 * 2^{14} + 1 * 2^{13} + 1 * 2^{12} +1 * 2^{11} + 0 * 2^{10} + 0 * 2^9 + 0 * 2^8 + 1 * 2^7 + 1 * 2^6 + 1 * 2^5 + 0 * 2^4 + 1*2^3 + 1 * 2^2 + 0 * 2^1 + 1 * 2^0

(1010 1000 1011 1000 1110 1101)_2 = 11057389

Solving (c): To base 16

i.\ (1011 1110 1101 1011 1010)_2

First, convert to base 10

In (b)

(1011 1110 1101 1011 1010)_2 = 781754

Next, is to divide 781754 by 16 and keep track of the remainder

781754/16\ |\ 48859\ R\ 10

48859/16\ |\ 3053\ R\ 11

3053/16\ |\ 190\ R\ 13

190/16\ |\ 11\ R\ 14

11/16\ |\ 0\ R\ 11

Write out the remainder from bottom to top

(11)(14)(13)(11)(10)

In hexadecimal

A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.

(11)(14)(13)(11)(10)=BEDBA

So:

(1011 1110 1101 1011 1010)_2 = BEDBA

ii.\ (1010 1000 1011 1000 1110 1101)_2

In b

(1010 1000 1011 1000 1110 1101)_2 = 11057389

Next, is to divide 11057389 by 16 and keep track of the remainder

11057389/16\ |\ 691086\ R\ 13

691086/16\ |\ 43192\ R\ 14

43192/16\ |\ 2699\ R\ 8

2699/16\ |\ 168\ R\ 11

168/16\ |\ 10\ R\ 8

10/16\ |\ 0\ R\ 10

Write out the remainder from bottom to top

(10)8(11)8(14)(13)

In hexadecimal

A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.

(10)8(11)8(14)(13) = A8B8ED

So:

(1010 1000 1011 1000 1110 1101)_2 =  A8B8ED

Solving (d): To octal

(i.)\ 74510

Divide 74510 by 8 and keep track of the remainder

74510/8\ |\ 9313\ R\ 6

9313/8\ |\ 1164\ R\ 1

1164/8\ |\ 145\ R\ 4

145/8\ |\ 18\ R\ 1

18/8\ |\ 2\ R\ 2

2/8\ |\ 0\ R\ 2

Write out the remainder from bottom to top

74510_8= 221416

(ii.)\ 67210

Divide 67210 by 8 and keep track of the remainder

67210/8\ |\ 8401\ R\ 2

8401/8\ |\ 1050\ R\ 1

1050/8\ |\ 131\ R\ 2

131/8\ |\ 16\ R\ 3

16/8\ |\ 2\ R\ 0

2/8\ |\ 0\ R\ 2

Write out the remainder from bottom to top

67210_8 = 203212

8 0
3 years ago
Given two integers as user inputs that represent the number of drinks to buy and the number of bottles to restock, create a Vend
Zanzabum

Answer:

import java.util.Scanner;

class Main {

 public static void main (String args[])

 {

   Scanner input = new Scanner(System.in);

   VendingMachine machine = new VendingMachine(20);

   System.out.print("Enter nr to purchase: ");

   int nrPurchased = input.nextInt();

   System.out.print("Enter nr to re-stock: ");

   int nrRestock = input.nextInt();

   machine.Transaction(nrPurchased, nrRestock);

   input.close();

 }

}

class VendingMachine {

 private int inventory;

 public VendingMachine(int initialInventory) {

   inventory = initialInventory;

 }

 public void Transaction(int nrToBuy, int nrToRestock) {

   inventory += nrToRestock - nrToBuy;

   System.out.printf("Inventory: %d bottles.\n", inventory);

 }

}

7 0
3 years ago
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