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Andrej [43]
3 years ago
10

What mass of NaOH must be used to prepare 2.5 L of a 0.010 M solution

Chemistry
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

m = 1\,g

Explanation:

The molarity is the ratio of the amount of moles solvent to volume of the solute.

0.010\,M = \frac{0.010\,moles\,NaOH}{1\,L}

The quantity of solute is determined by simple rule of three:

n = \left(\frac{2.5\,L}{1\,L} \right)\cdot (0.010\,mole)

n = 0.025\,moles

The molecular weight of NaOH is 39.997\,\frac{g}{mole}, the mass of solute is:

m = 1\,g

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n = \text{347 mi} \times \dfrac{\text{1 gal}}{\text{36.5 mi}}\times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{679.5 g}}{\text{1L}} \times \dfrac{ \text{1 mol}}{\text{100.20 g}}= \text{244 mol}

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At 20 °C and 1 atm, the molar volume of a gas is 24.0 L.  

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The power station is only 85 % efficient.  

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