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Semenov [28]
3 years ago
7

How many moles are in 1.806 x 1024 molecules of bromine?

Chemistry
2 answers:
Pepsi [2]3 years ago
7 0
<h3>Answer:</h3>

2.999 mol Br

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.806 × 10²⁴ molecules Br

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 1.806 \cdot 10^{24} \ molecules \ Br(\frac{1 \ mol \ Br}{6.022 \cdot 10^{23} \ molecules \ Br} ) = 2.999 mol Br

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

Our final answer is already in 4 sig figs, so there is no need to round.

Nata [24]3 years ago
5 0

Answer:

\boxed {\boxed {\sf About \ 2.999 \ moles \ of \ bromine}}

Explanation:

To convert from moles to molecules, we must use <u>Avogadro's Number</u>.

6.022*10^{23}

This tells us the number of particles (atoms, molecules, ions, etc) in 1 mole. In this problem, the particles are molecules of bromine in 1 mole of bromine.

6.022*10^{23} \ molecules \ Br / 1 \ mol \ Br

1. Convert from moles to molecules

Use Avogadro's number as a fraction or ratio.

\frac{6.022 *10^{23} \ molecules \ Br}{1 \ mol \ Br}

Multiply this fraction by the given number of bromine molecules.

1.806 *10^{24} molecules \ Br *\frac{6.022 *10^{23} \ molecules \ Br}{1 \ mol \ Br}

Flip the fraction so the molecules of bromine can cancel out.

1.806 *10^{24} \ molecules \ Br* \frac{1 \ mol \ Br}{6.022 *10^{23} \ molecules \ Br}

1.806 *10^{24} * \frac{1 \ mol \ Br}{6.022 *10^{23}}

Multiply and condense the expression into 1 fraction.

\frac{1.806 *10^{24} \ mol \ Br}{6.022 *10^{23} }

Divide.

2.999003653 \ mol \ Br

2. Round

The original measurement, 1.806*10^24 has 4 significant figures (1, 8, 0, and 6). We must round our answer to 4 sig figs. For the answer we found, that is the thousandth place.

2.999003653 \ mol \ Br

The 0 in the ten-thousandth place tels us to leave the 9 in the thousandth place.

\approx 2.999 \ mol \ Br

There are about <u>2.999 moles of bromine</u> in 2.806 *10^23 molecules.

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