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3 years ago

Solve for x. ax-bx=k

Mathematics

2 answers:

Otrada [13]3 years ago

8 0

Answer: a = b + kx^-1

Step-by-step explanation:

Simplifying

ax + -1bx = k

Solving

ax + -1bx = k

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'bx' to each side of the equation.

ax + -1bx + bx = bx + k

Combine like terms: -1bx + bx = 0

ax + 0 = bx + k

ax = bx + k

Divide each side by 'x'.

a = b + kx^-1

Simplifying

a = b + kx^-1

dolphi86 [110]3 years ago

3 0

Answer:

x= k/a-b

Step-by-step explanation:

Move all terms to the left side and set equal to zero as well as each factor.

Hope this helps.

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Help please :(((((( ill givve brainly

SVETLANKA909090 [29]

Answer:

2.86 hours = £26.57

Step-by-step explanation:

5 builders = 3.5 hours

Express it in ratio form:

5 : 3.5 (B1:H1)

However, on Tuesday 2 builders(B2) are available. We can set up a proportion to find the number of hours.

Since This is an inverse proportion, it will be written like:

=> B1:H1 = H2:B2

Where H2 = x(no. of hours)

=> 5 : 3.5 = x : 2

Product of means = Product of Extremes

=> 5*2 = 3.5x

=> 10 = 3.5 x

Dividing both sides by 3.5

=> x = 2.86 hours

Now, On Tuesday:

1 hour = £9.3

For 2.86 hours,

2.86 hours = £9.3 × 2.86

2.86 hours = £26.57

6 0

3 years ago

Read 2 more answers

A rectangular box has a base that is 4 times as long as it is wide. The sum of the height and the girth of the box is 200 feet.

enyata [817]

Answer: V(W) = (1/3)*(*W^2*800ft - 8W^3) and the domain is 0 < W < 100ft.

Step-by-step explanation:

The dimensions of the box are:

L = length

W = width

H = heigth.

We know that:

L = 4*W

And the girth of a box is equal to: G = 2*W + 2*H

then we have:

2*W + 2*H + H = 200ft

2W + 3*H = 200ft

Then we have two equations:

L = 4*W

2W + 3*H = 200ft

We want to find the volume of the box, which is V = W*L*H

and we want in on terms of W.

Then, first we can replace L by 4*W (for the first equation)

and:

2*W + 3*H = 200ft

3*H = 200ft - 2*W

H = (200ft - 2*W)/3.

then the volume is:

V(W) = W*(4*W)*(200ft - 2*W)/3

V(W) = (1/3)*(*W^2*800ft - 8W^3)

The domain of this is the set of W such that the volume is positive, then we must have that:

W^2*800ft > 8W^3

To find the maximum W we can see the equality (the minimum extreme is 0 < W, because the width can only be a positive number)

W^2*800ft = 8W^3

800ft = 8*W

100ft = W.

This means that if W is equal or larger than 100ft, the equation gives a negative volume.

Then the domain is 0 < W < 100ft.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%283a%5E2b%29%5E3%7D%7B9%28ab%29%5E4%7D" id="TexFormula1" title="\frac{(3a^2b)^3}{9(

VladimirAG [237]

You first multiply the outside exponents into the numbers in the parentheses.

When you have an exponent being multiplied directly to another exponent, you multiply the exponents together.

For example(because I am a bad explainer):

$(x^{2} )^4= x^{2(4)} = x^8$

$(x^4)^3 = x^{4(3)} = x^{12}$

When you divide an exponent by an exponent, you subtract the exponents

For example:

$\frac{x^4}{x^1} =x^{4-1}=x^3$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

$x^{-3}=\frac{1}{x^3}$

$\frac{1}{y^{-5}}=\frac{y^5}{1}=y^5$

$\frac{(3a^2b)^3}{9(ab)^4}$

You can think of it like this if you want:

$\frac{(3^1a^2b^1)^3}{9(a^1b^1)^4}$ Now multiply the outside exponents into the exponents in the parentheses

$\frac{3^3a^6b^3}{9(a^4b^4)} =\frac{27a^6b^3}{9(a^4b^4)}$ Divide 27 and 9

$\frac{3a^6b^3}{a^4b^4} =(3)(a^{6-4})(b^{3-4})=(3)(a^2)(b^{-1})=(3)(a^2)(\frac{1}{b^1})=\frac{3a^2}{b}$

Your answer is $\frac{3a^2}{b}$

5 0

3 years ago

Find the area of a triangle whose base is 10 mm, and its height is 15 mm.

hjlf

Answer:

75mm²

Step-by-step explanation:

Area of a triangle

1/2 × base × height

= 1/2 × 10mm × 15mm

= 75mm²

5 0

3 years ago

Find the slope of a line parallel to the line containing (-6.1) and (3,-2).

aleksley [76]

Find what is in the middle of them from where the lines meet

6 0

3 years ago

Solve for x. ax-bx=k​

Solve for x. ax-bx=k