Answer:
a = 25 cm/s²
Explanation:
Given,
The mass of the cart, m = 1 Kg
The acceleration of the cart, a = 50 cm/s²
The string with clay hanging off the ramp exerts a force, F on the cart (neglecting the tension in the string)
F = m x a
= 1 Kg X 50 cm/s²
= 50 Kg cm/s²
Hence the force exerted by the clay hanging off the ramp on the cart, F = 50 Kg cm/s²
If the mass of the cart is doubled '2 Kg', the same magnitude of the force acts on the cart.
Therefore, from the equation,
F = m x a
50 Kg cm/s² = 2 Kg x a
a = 50 Kg cm/s² / 2 Kg
= 25 cm/s²
Hence, the acceleration of the cart is, a = 25 cm/s²
Answer:
measurable period during which an action, process, or condition exists or continues
Explanation:
Answer:
The football must be launched whit an angle of 20,487 degrees to reach a maximum height of 10 meters.
Explanation:
To solve this problem we use the parabolic motion equations:
We define:
: total initial speed =
:initial speed component in vertical direction (y)
=
: vertical speed at any point on the parabolic path
g= acceleration of gravity= 9,8
= angle that forms the total initial velocity with the ground
Equation of the speed of the football in the vertical direction :
Equation (1)
We replace, in the equation (1):
Equation(2)
Angle calculation
The speed of the football in the vertical direction gradually decreases until its value is zero when it reaches the maximum height.
We replace , in the equation (2)
°
Answer:The football must be launched whit an angle of 20,487 degrees to reach a maximum height of 10 meters.
Work done = force × distance travelled in the direction of the force
Force= 2(9.81) = 19.62N
WD= 19.62×130= 2550.6Nm