Answer:
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Explanation:
1N=1kg•m/s^2 so the answer is 3N
Explanation:
It is given that,
The acceleration of the toboggan,
Initial speed of the toboggan, u = 0
We need to find the distance covered by the toboggan. Using the second equation of motion as :
At t = 1 s
At t = 2 s
At t = 3 s
Hence, this is the required solution.
Note: if the professor wants the distance between the m = 0 and m = 1 maxima to be 25 cm
Answer:
d = 1.0128×10⁻⁵m
Explanation:
given:
length L = 4.0m
maximum distance between m = 0 and m = 1 , y = 25cm = 0.25m
wavelength λ = 633nm = 633×10⁻⁹m
note:
dsinθ = mλ (constructive interference)
where d is slit seperation, θ is angle of seperation , m is order of interference , and λ is wavelength
for small angle
sinθ ≈ tanθ
mλ
d = 1.0128×10⁻⁵m