Answer:
(a) Magnitude of static friction force is 109 N
(b) Minimum possible value of static friction is 0.356
Solution:
As per the question;
Horizontal force exerted by the girl, F = 109 N
Mass of the crate, m = 31.2 kg
Now,
(a) To calculate the magnitude of static friction force:
Since, the crate is at rest, the forces on the crate are balanced and thus the horizontal force is equal to the frictional force, f:
F = f = 109 N
(b) The maximum possible force of friction between the floor and the crate is given by:

where
N = Normal reaction = mg
Thus

For the crate to remain at rest, The force exerted on the crate must be less than or equal to the maximum force of friction.




Answer:
convex lens
Explanation:
An image is form in retina with light rays converging most at cornea and upon entering and existing the lens.Rays from top and bottom of the object are traced and produce an inverted image on the retina
1.b 2.c 3.a 4.b 5.d 6.a 7.a 9.idk 10.c hope thes helps have a nice day and God bless
Answer:
A. 51.42 m.
B. 17.14 s.
Explanation:
Using equations of motion:
vf^2 = vi^2 + 2 * aS
Where,
vf = final velocity
a = acceleration
S = distance to which swan traveled
vi = 0 m/s
6.00^2 = 2 * 0.350S
S = 36/0.7
= 51.42 m.
B.
vf = vi + at
6 = 0 + 0.35t
t = 6/0.35
= 17.14 s.