Answer : We can produce 125.7 g of 
.
Explanation : The reaction will be
The molecular mass of 
is 64.1 g/mol
and molecular mass of 
is 34.1 g/mol
For every mole of we would need twice of moles, so for every 3 moles of we need 16 moles of
Now, we can calculate number of moles
2.61 X (3/16) = 0.49 moles
Here, the molecular mass of is 256.8 g
multiplying it with the number of 0.49 moles we get, 256.8 X 0.49 = 125.7 g of .
Hence, 125.7 g of will be produced.
Answer:
205 K (to 3 significant figures)
Explanation:
Assuming that 4 moles of the gas behaves like an ideal gas and obey the kinetic molecular theory.
Let's apply the ideal gas law, pV= nRT.
Here p denotes the pressure of the gas, V is for volume, n is the number of moles of the gas, R is the universal gas constant and T is the temperature.
Substitute the given information into the equation:
5.6 atm ×12 L= 4 mol ×R ×T
Since pressure is in atm and volume is in L, we can use R= 0.08206 L atm K⁻¹ mol⁻¹.
5.6 atm ×12 L= 4 mol ×0.08206 L atm K⁻¹ mol⁻¹ ×T
T= 67.2 ÷0.32824
T= 204.73 (5 s.f.)
T= 205 K (3 s.f.)
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A i hope that helped i love you guys have a great day
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