Ask question

Ask question

All categories

3 years ago

5

In order for a color to be seen by a human, the light must be

1 answer:

ololo11 [35]3 years ago

8 0

In the part of the spectrum our eyes can detect (a spectrum is an arry of entities, as light waves or particles, ordered in accordance with the magnitudes of a common physical property, as wavelength or mass) Hope this helps you :D

You might be interested in

Which object moves in simple harmonic motion?\

Rina8888 [55]

<h2>Answer:Stretched rubber band with an mass</h2>

Explanation:

Simple harmonic motion requires a restoring force.

Simple harmonic motion should be periodic.

Option A:

When a rubber band is stretched,the internal forces of the rubber band pulls the band inside.So,internal forces are the restoring forces in a rubber band.

The motion is periodic as well since the the rubber band makes to an fro motion expanding ans contracting.

So,this performs SHM.

Option B:

There is no restoring force and no periodicity.

So,this is not SHM.

Option C:

There is no restoring force and no periodicity.

So,this is not SHM.

Option D:

There is periodicity but no restoring force.

So,this is not SHM.

3 0

3 years ago

Which of the following is a field force

IRINA_888 [86]

So basically my morning has been good so far I woke up with a. Headache tho maybe a I have a tumor idk

8 0

3 years ago

A projectile is launched vertically from the surface of the Moon with an initial speed of 1360 m/s. At what altitude is the proj

LenaWriter [7]

Answer:

485520 m

Explanation:

$v_{o}$ = initial velocity of the projectile = 1360 m/s

$v_{f}$ = final velocity of the projectile = $\left ( \frac{2}{5} \right )v_{_{o}}$ = $\left ( \frac{2}{5} \right )(1360)$ = 544 m/s

a = acceleraton due to gravity on moon = - 1.6 m/s²

h = Altitude of the projectile

Using the kinematics equation

$v_{f}^{2} = v_{o}^{2} + 2 a h$

Inserting the values

$544^{2} = 1360^{2} + 2 (-1.6) h$

h = 485520 m

3 0

3 years ago

A ball strikes a wall. It exerts a force of 10 N to the left against the wall and bounces off. What force does the wall exert on

Galina-37 [17]

The wall exerts a force of equal magnitude but in the opposite direction. So the force by the wall is 10 N to the right.

6 0

3 years ago

Read 2 more answers

Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.

ozzi

Answer:

The thrust is $6\times 10^6\ N$

Explanation:

Given that,

Mass of gas, $m=1.5\times 10^3\ kg$

The rate at which the gas is expelling, $\dfrac{dv}{dt}=4\times 10^{3}\ m/s$

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

$F=\dfrac{p}{t}$

Also, p = mv

$F=\dfrac{mv}{t}$

So,

$F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N$

So, the thrust is $6\times 10^6\ N$

3 0

3 years ago