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Helen [10]
4 years ago
10

How fast will a ball be traveling if it falls for 5 seconds​

Physics
1 answer:
Elenna [48]4 years ago
7 0

Gravity accelerates you at 9.8 meters per second per second. After one second, you're falling 9.8 m/s. After two seconds, you're falling 19.6 m/s, and so on.
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How long does it take for an 8 kg pumpkin to hit the ground if dropped from a height of 55 m.
Sati [7]

Answer:

t = 3.35 s

Explanation:

It is given that,

Mass of a pumpkin, m = 8 kg

It is dropped from a height of 55 m

We need to find the time taken by it to hit the ground.

Initial velocity of the pumpkin, u = 0

Using second equation of motion to find it as follows :

h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2(55)}{9.8}} \\\\t=3.35\ s

So, it will take 3.35 seconds to hit the ground.

7 0
3 years ago
I need Help Fast ASAP<br> Also, SHOW YOUR WORK<br> WILL MARK BRAINLIEST!!!!<br> 100 points!!!
denis-greek [22]

Answer

7 is d ii is a iii is d

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5 is x is 0 = 145 and y is 128

6 is a

1 is 10.20

2 is 151 and 5010

3 is < is 0 and I is y

9 is 3.0 and 2.0

hope this helps

6 0
3 years ago
Identify which one is chemical change, chemical property,physical change and physical property
Ulleksa [173]

Answer:

Heat conductivity: Physical property

Silver tarnishing: chemical change

Sublimation: physical change

Magnetizing steel: physical property

Length of a metal object: physical property

Shortening melting: physical property

exploding dynamite: chemical change

combustible: chemical property

water freezing: physical change

Acid resistance: chemical property

brittleness: physical property

milk souring: chemical change

baking bread: chemical change

Explanation:

First you need to understand the differences between physical and chemical change; physical and chemical property.

<u>Physical properties vs chemical properties:</u>

Physical properties are properties that you can observe without changing the substance's composition. This means you can measure these properties without changing them chemically.

Chemical properties, on the other hand, are properties are not as direct. These properties are generally determined by the way the react with other substances changing their composition.

<u>Physical changes vs chemical changes:</u>

A substance that undergoes physical change does not change in chemical composition. They may look physically different in terms of size and shape, but overall, their chemical composition remains constant. The best example would be water. Water can change phases, from solid to liquid when they melt. Essentially, they look like different substances, but the change is only physical and not chemical.

Chemical change, is different by the fact that they change in chemical composition. Bonds are broken and/or made through the reaction, which changes them not only physically but chemically as well. Some of the most indicative signs of a chemical change occurring are: change in color, odor, production of gas, production of light/heat.

4 0
3 years ago
2001240Determine the specific kinetic energy of a mass whose velocity is 40 m/s, in kJ/kg.
guapka [62]

Answer:

The specific kinetic energy of a mass is 0.8 kJ/kg

Explanation:

Given that,

Velocity = 40 m/s

Specific kinetic energy is the kinetic energy per unit mass.

We need to calculate the specific kinetic energy

Using formula of specific kinetic energy

K.E=\dfrac{\dfrac{1}{2}mv^2}{m}

K.E=\dfrac{v^2}{2}

Put the value into the formula

K.E=\dfrac{40^2}{2}

K.E=800\ J/kg

We know that,

1 kJ = 1000 J

or, 1J=0.001 KJ

The specific energy is

K.E=800\times0.001

K.E=0.8\ kJ/kg

Hence, The specific kinetic energy of a mass is 0.8 kJ/kg

6 0
3 years ago
A snowball starting at rest rolls down a hill and reaches 5 m/s. If the hill is
Lostsunrise [7]

Answer:

The acceleration of the snowball is 0.3125

Explanation:

The initial speed of the snowball up the hill, u = 0

The speed the snowball reaches, v = 5 m/s

The length of the hill, s = 40 m

The equation of motion of the snowball given the above parameters is therefore;

v² = u² + 2·a·s

Where;

a = The acceleration of the snowball

Plugging in the values, we have;

5² = 0² + 2 × a × 40

∴ 2 ×  40 × a  = 5² = 25

80 × a = 25

a = 25/80 = 5/16

a = The acceleration of the snowball = 5/16 m/s².

The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .

4 0
3 years ago
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