Answer:
10m
Explanation:
The object distance and image distance is the same from the mirror. so the image is 5m behind the mirror.
5+5=10
Answer:
Melting, its like an ice cube(solid) melting in the sun into water(liquid)
Answer:
t = 0.85[s]
Explanation:
To solve this problem we must make a complete description of this. By doing an internet search, we find the description of this problem as if of the question.
<u>Description</u>
<u />
"An alligator swims to the left with a constant velocity of 5 m s when the alligator season a bird straight ahead the alligator speeds up with a constant acceleration of 3 m/s^2 leftward until it reaches a final velocity of 35 Ms left work how many seconds does it take the alligator to speed up from 5 m/s to 35 m/s".
To solve this problem we must identify the initial data:
v0 = initial velocity = 5 [m/s]
a = acceleration = 3 [m/s^2]
vf = final velocity = 35[m/s]
t = time = ?
Using the following kinematic equation, we can find the time that is required.
Answer:longitudinal waves
Explanation:
They are longitudinal waves
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Below is the solution:
<span>T2cos(30) - T1cos(50) = 0
</span><span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span><span>T2cos(30) - T1cos(50) = 0 --> T1 = T2cos(30)/cos(50)
</span>
<span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span>(<span>T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> Solve for T2
</span><span>T1 = -T1cos(50)i + T1sin(50)j
T2 = T2cos(30)i + T2sin(3)j
</span>
<span>(T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 -->
T2[(cos(30)/cos(50))sin(50) + sin(30)] = 75*(grav) -->
T2 = 75*grav/ [(cos(30)/cos(50))sin(50) + sin(30)]
</span>
<span> T2 = 1566.49 </span>