Explanation:
The given data is as follows.
= 10 mM =
M
= 750 ml,
= 5 ml
= ?
Therefore, calculate the molarity of given NaCl stock as follows.


= 1.5 M
Thus, we can conclude that molarity of given NaCl stock is 1.5 M.
Pretty sure it’s Mixture if I’m not wrong
Explanation:
Respuesta: La masa atómica del carbono (C) es 12 g/mol; para el oxígeno (O) es de 16 g/mol. Esto significa que 6.022 x 1023 átomos de carbono pesan 12 gramos. Según esto, el peso molecular del CO2 es: 12 g/mol [C] + 2 x 16 g/mol [O2] = 44 g/mol
Answer:
7) 50 8)4
Explanation:
I answered the question what do you want to gave me