Now that we have put a coefficient of 3 in front of caso4, what coefficient should go in front of cacl2 to balance calcium (ca)?
2 answers:
Answer:
3 (three).
Explanation:
Hello,
Perhaps, you are talking about the following undergoing chemical reaction:
Thus, balancing it by inspection, one obtains:
In such a way, a 3 (three) must be placed in front of the calcium chloride in order to balance calcium and consequently the rest of the chemical reaction.
Best regards.
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Answer:
a) 1,6%
b) 64,775 g/mol
c) 3,6×10⁻² M
d) 2,3×10⁻³ g/mL
Explanation:
a) The mass fractium of helium is obtained converting the moles of the four gases to grams with molar weight and then caculating of the total of grams how many are of helium, thus:
- Helium: 0,25 moles ×
= 1 g of Helium
- Argon: 0,25 moles ×
= 10 g of Argon
- Krypton: 0,25 moles ×
= 20,95 g of krypton
- Xenon: 0,25 moles ×
= 32,825 g of Xenon
Total grams: 1g+10g+20,85g+30,825g= 62,675 g
Mass fraction of helium: × 100 = <em>1,6%</em>
<em />
<em>The mass fraction of Helium is 1,6%</em>
<em />
<em>b)</em><em> </em>Because the mole fraction of all gases is the same the average molecular weight of the mixture is:
= 64,775 g/mol
c) The molar concentration is possible to know ussing ideal gas law, thus:
= M
Where:
P is pressure: 150 kPa
R is gas constant: 8,3145
T is temperature: 500 K
And M is molar concentration. Replacing:
M = 3,6×10⁻² M
d) The mass density is possible to know converting the moles of molarity to grams with average molecular weight and liters to mililiters, thus:
3,6×10⁻² ×
×
=
2,3×10⁻³ g/mL
I hope it helps!