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Afina-wow [57]
3 years ago
5

An object has a mass of 441 g and a volume of 10cm3

Chemistry
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

44.1g/cm3

Explanation:

d=m/v

=441/10

=44.1 g/cm3

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A. 207 kJ<br> B. 4730 kJ<br> O C. 9460 kJ<br> O D. 414 kJ
slavikrds [6]

Answer:

C = 9460 Kj

Explanation:

Given data:

Mass of copper = 2kg

Latent heat of vaporization = 4730 Kj/Kg

Energy required to vaporize 2kg copper = ?

Solution:

Equation

Q= mLvap

by putting values,

Q= 2kg ×  4730 Kj/Kg

Q = 9460 Kj

3 0
3 years ago
Emperical formula of carbon dioxide
Stells [14]

CO2 is the emperical formula of carbon dioxide

6 0
2 years ago
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Based on the nebular theory of the solar system formation, explain how our solar system is formed.
Alika [10]

the nebular theory states that the solar systems developing <u><em>rotations </em></u>revolve around sun. it is located in the milky-way. revolving around the <u><em>sun</em></u>, with <u><em>gravity</em></u> pulling it, an interstellar cloud of dust and gas, is formed. (i.e. the nebula that we are speaking)

this formation is a<u><em> protostar</em></u>. the idea in the theory states that the <u><em>nebula</em></u> has flattened into a <u><em>disk</em></u> called the "protoplanetary disk"; and over time, the debreis eventually formed this disk. (i.e. creating the milky-way)

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6 0
2 years ago
23) What is the volume of 2.454 x 1024 atoms of nitrogen gas at STP?
earnstyle [38]

Answer:

d) V =  91.3 L

Explanation:

Given data:

Volume of nitrogen = ?

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Number of atoms of nitrogen = 2.454×10²⁴ atoms

Solution:

First of all we will calculate the number of moles of nitrogen by using Avogadro number.

1 mole = 6.022×10²³ atoms

2.454×10²⁴ atoms × 1 mol / 6.022×10²³ atoms

0.407×10¹ mol

4.07 mol

Volume of nitrogen:

PV = nRT

1 atm × V = 4.07 mol ×0.0821 atm.L /mol.K ×273.15 K

V =  91.3 atm.L /1 atm

V =  91.3 L

3 0
3 years ago
Fe2O3+2Al=Al2O3+2Fe
True [87]
We determine the limiting reactant by using the moles present in the equation and the actual moles.
According to equation, ratio of Fe₂O₃ : Al = 1 : 2
Actual moles of Fe₂O₃ = 187.3 / (56 x 2 + 16 x 3)
= 1.17
Actual moles of Al = 94.51 / 27
= 3.5
Fe₂O₃ is limiting. Fe₂O₃ required:
(moles Al)/2 = 3.5/2 = 1.75
Moles to be added = 1.75 - 1.17
= 0.58
Mass to be added = moles x Mr
= 0.58 x (56 x 2 + 16 x 3)
= 92.8 grams
6 0
2 years ago
Read 2 more answers
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