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victus00 [196]
1 year ago
11

B-ad=3c+r solve for c

Chemistry
1 answer:
DENIUS [597]1 year ago
7 0

By making c the subject of formula in the given equation, the value "c" is equal to c = (B - ad - r)/3.

<h3>What is an equation?</h3>

An equation can be defined as a mathematical expression which shows that two (2) or more thing are equal.

In this exercise, you're required to solve for c from the given mathematical expression (equation) by making it the subject of formula. This ultimately implies that, all the other variables would be defined in terms of c and they would all be on the same side of the "equal to" symbol.

Making c the subject of formula, we have:

B - ad = 3c + r

3c = B - ad - r

Dividing both sides by 3, we have:

3c/3 = (B - ad - r)/3

c = (B - ad - r)/3.

Read more on subject of formula here: brainly.com/question/21140562

#SPJ1

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Paliwanag ang kahalagahan ng papa at ng holy roman emperor sa panahong midieval.
Doss [256]

Explanation:

The Holy Roman Empire (Latin: Sacrum Imperium Romanum; German: Heiliges Römisches Reich), also termed as the First Reich, was a multi-ethnic complex of territories in Western and Central Europe that developed during the Early Middle Ages and continued until its dissolution in 1806 during the Napoleonic Wars.[6] The largest territory of the empire after 962 was the Kingdom of Germany, though it also included the neighboring Kingdom of Bohemia and Kingdom of Italy, plus numerous other territories, and soon after the Kingdom of Burgundy was added. However, while by the end of the 15th century the Empire was still in theory composed of three major blocks – Italy, Germany, and Burgundy – in practice only the Kingdom of Germany remained, with the Burgundian territories lost to France and the Italian territories, ignored in the Imperial Reform, although formally part of the Empire, were splintered into numerous de facto independent territorial entities.[7][8][9][10] The external borders of the Empire did not change noticeably from the Peace of Westphalia – which acknowledged the exclusion of Switzerland and the Northern Netherlands, and the French protectorate over Alsace – to the dissolution of the Empire. By then, it largely contained only German-speaking territories, plus the Kingdom of Bohemia, the southern Netherlands and lands of Carniola. At the conclusion of the Napoleonic Wars in 1815, most of the Holy Roman Empire was included in the German Confederation.

in yr language:

Ang Holy Roman Empire (Latin: Sacrum Imperium Romanum; German: Heiliges Römisches Reich), na tinawag din bilang First Reich, ay isang multi-etniko na kumplikado ng mga teritoryo sa Kanluran at Gitnang Europa na d

3 0
3 years ago
Please help!!
andriy [413]

(I know this is late so hopefully other people find it helpful)

<u>Answer</u>: Solid Cu  

Since this is a <u>voltaic cell</u>:

<u>Copper</u> is the cathode, therefore having a positive charge.

<u>Zinc</u> is the anode, therefore having a negative charge.

(Also, I took the exam and it's correct; good luck everyone!)

3 0
2 years ago
Which law relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions?
kozerog [31]
Ideal Gas law PV=nRT

P- pressure(atm)
V-volume( liter)
R- gas constant
T- temperature(kelvin)
n - number of moles
6 0
3 years ago
Read 2 more answers
Which are the hybrid orbitals of the carbon atoms in the following molecules? (a) H3C―CH3 sp sp2 sp3 (b) H3C―CH═CH2 sp sp2 sp3 (
kherson [118]

Answer:

(a)  sp³    sp³

   H₃<u>C</u> - <u>C</u>H₃

(b)     sp³           sp²

     H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂

                sp²

(c)     sp³        sp    

    H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH

              sp         sp³

(d)     sp³    sp²    

       H₃<u>C</u> - <u>C</u>H=O

Explanation:

Alkanes or the carbons with all the single bonds are sp³ hybridized.

Alkenes or the carbons with double bond(s) are sp² hybridized.

Alkynes or the carbons with triple bond are sp hybridized.

Considering:

(a) H₃C-CH₃ , Both the carbons are bonded by single bond so both the carbons are sp³ hybridized.

Hence,

 sp³    sp³

H₃<u>C</u> - <u>C</u>H₃

(b) H₃C-CH=CH₂ , The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp² hybridized because they are bonded by double bond.

Hence,

   sp³           sp²

H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂

         sp²

(c) H₃C-C≡C-CH₂OH , The carbons of the methyl group and alcoholic group are sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp hybridized because they are bonded by triple bond.

Hence,

   sp³        sp    

H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH

         sp         sp³

(d)CH₃CH=O, The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The other carbon is sp² hybridized because it is  bonded by double bond to oxygen.

Hence,

   sp³    sp²    

 H₃<u>C</u> - <u>C</u>H=O

     

8 0
3 years ago
Several kinds of bears are found on Earth. Most bears are brown or black, but one type of bear, the polar bear, is white. What p
jeka94

This is called adaptation. An example would be a polar bear with white fur. They have this to be more efficent hunters, as they use it as a type of camouflage in order to sneak up on prey. Brown bear use this in the same way but their environment requires them to be brown in order to blend in beter with trees. So basicly adaptation

7 0
3 years ago
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