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vladimir1956 [14]
3 years ago
14

1.567 + 2.345 - 1.83(5)

Mathematics
2 answers:
g100num [7]3 years ago
6 0

Answer:

-5.238

Step-by-step explanation:

<u>Step 1:  First multiply</u>

1.567 + 2.345 - 1.83(5)

<em>1.567 + 2.345 - 9.15</em>

<em />

<u>Step 2:  Add the first two numbers</u>

(1.567 + 2.345) - 9.15

<em>3.912 - 9.15</em>

<em />

<u>Step 3:  Add the next two numbers</u>

3.912 - 9.15

<em>-5.238</em>

<em />

Answer:  -5.238

soldier1979 [14.2K]3 years ago
4 0

Answer:

-5.238

Step-by-step explanation:

1.567+2.345=3.912-1.83(5)=

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A man walked north 119 feet and then west 120 feet. Find the shortest distance between the start and end points.​
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169 feet

Step-by-step explanation:

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I’m thinking the answer is A :)<br> A. Y=2x+4<br> B. Y=4x+2 <br> C. Y=2x-4<br> D. Y=4x-2
madreJ [45]

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

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with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 4) ← 2 points on the line

m = \frac{4-0}{0-(-2)} = \frac{4}{0+2} = \frac{4}{2} = 2

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A car is 160 inches long.
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Question 2:
Ugo [173]

With the frequecy distribution shown in the 50 cities of pakistan,

  • range = 18
  • mean = 18.1
  • median = 19.8333
  • mode = 19.125
  • kurtosis = 2.7508
  • Standard deviation = 3.75

<h3>How to find the Range</h3>

= highest value - lowest value

= 26.5 - 8.5

= 18

<h3>How to find the mean</h3>

= ∑ f x / ∑ f

= ∑ f x / N

= 905 / 50

= 18.1

median

= lower limit + ( N/2 - C ) * h / ( frequency of the class interval )

C = cumulative frequency preceeding to the median class frequency

h = class interval

= 18.5 + ( 50 / 2 - ( 5 + 12 ) ) * 3 / 18

= 18.5 + 1.3333

= 19.8333

<h3>How to find the mode</h3>

The mode is the value with the highest frequency occurence. This is under class 18 - 20

mode = lower limit + ( ( f1 - f0 ) / (2*f1 - f0 - f2 ) ) * h

f1 = fequency of the modal class

f0 = freqency of the preceeding modal class

f2 = frequency of the next modal class

h = class interval

= 18.5 + ( ( 18 - 12 ) / (2 * 18 - 12 - 8 )  ) * 3

= 18 + ( 0.375 ) * 3

= 19.125

<h3>How to find the standard deviation </h3>

= sqrt ( 1 / N ∑ f ( x - x' )^2 )

= sqrt (1  / 50 * 706.5

= 3.7589

<h3>How to solve for relative dispersion </h3>

=  standard deviation / mean

= 3.7589 / 3

= 1.2530

<h3>What is the variance? </h3>

= ( standard deviation )^2

= ( 3.7589 )^2

= 14.1293

<h3>How to solve for kurtosis</h3>

=  ∑ f ( x - x' )^4 / ( N * ( standard deviation )^4 )

= 27459.405 / ( 50 * 3.7589^4 )

= 2.7509

Read more on frequency distribution here: brainly.com/question/1094036

4 0
2 years ago
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