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4 years ago

The movement of protons through atp synthase occurs from the

Physics

1 answer:

Lera25 [3.4K]4 years ago

5 0

Answer:

cytoplasm and channel gates

Explanation:

The movement originates from the cytoplasm. This is the fluid medium through which ions are shuttle from one place to another. However, though simple as it might appear to be, the movement requires carrier proteins. The are proteins that facilitate in the movement of the ions. These proteins have specially controlled gates called channel proteins. These are regulated proteins that open and close based on hydrogen ion concentration. These proteins are able to facilitate the movement of ATP molecules.

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What does a wedge do

maxonik [38]

It can be used to separate two objects or portions of an object, lift up an object, or hold an object in place.

4 0

4 years ago

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A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic fr

Ksivusya [100]

a) The initial speed of the bullet is 330.5 m/s

b) The collision is inelastic

c) The impulse is -2.97 kg m/s

Explanation:

The energy lost by the block while sliding (which is equal to the work done by friction) is equal to the kinetic energy of the block after the bullet has been embedded into it, therefore we can write

$KE=W$

$\frac{1}{2}(M+m)v^2=(\mu (M+m)g) d$

where

M = 1.20 kg is the mass of the block

m = 9.00 g = 0.009 kg is the mass of the bullet

v is the combined speed of bullet+block after the collision

$\mu = 0.20$ is the coefficient of friction

$g=9.8 m/s^2$ is the acceleration of gravity

d = 0.310 m is the distance through which the block slides

Solving for v,

$v=\sqrt{2gd}=\sqrt{2(9.8)(0.310)}=2.46 m/s$

This is the final velocity of the block+bullet after the collision.

Now we can apply the law of conservation of momentum: in fact, the total momentum of the system before the collision must be equal to the total momentum after the collision, so we get

$mu+MU = (m+M)v$

where

u is the initial velocity of the bullet

U = 0 is the initial velocity of the block (initially at rest)

v = 2.46 m/s

Solving for u,

$u=\frac{(m+M)v}{m}=\frac{(0.009+1.20)(2.46)}{0.009}=330.5 m/s$

To check whether the collision is elastic or inelastic, we just need to compare the total kinetic energy before and after the collision.

Before the collision, we have:

$K_i = \frac{1}{2}mu^2 = \frac{1}{2}(0.009)(330.5)^2=491.5 J$

While after the collision

$K_f = \frac{1}{2}(m+M)v^2 = \frac{1}{2}(0.009+1.20)(2.46)^2=3.7 J$

We see that the final kinetic energy is less than the initial kinetic energy: therefore, the collision is inelastic, since part of the energy has been converted into other forms of energy (e.g. thermal energy).

The impulse of the block is equal to its change in momentum, so:

$I=\Delta p =p_f - p_i = (m+M)v'-(m+M)v$

where

v' = 0, since the block comes to a stop

v = 2.46 m/s is the velocity of the block just after the collision

Substituting,

$I=0-(0.009+1.20)(2.46)=-2.97 kg m/s$

And the impulse is negative, because its direction is opposite to the direction of motion of the block (this means that the force exerted on the block, which is the force of friction, acts in the direction opposite to the motion of the block).

Learn more about kinetic energy and momentum:

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4 years ago

What is the weight of a ring tailed lemur that has a mass of 10 kg? Use w = mg (g = -9.8 m/s2)

Nana76 [90]

The correct answer was

98N

For Newtons 3rd Law Quiz K-12

6 0

3 years ago

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Calculate the temperature increase in a 1.00-kg sample of water that results from the conversion of gravitational potential ener

Llana [10]

To solve this problem it is necessary to apply the concepts concerning the conservation of both potential and thermodynamic energy of the body. That is to say that as the body has a loss of potential energy it is gained in the form of thermal energy on water. If the potential energy is defined as

$PE = mgh$

Where,

m= mass

g = Gravitational acceleration

h = Height

And thermal energy is obtained as

$Q = mC_p\Delta T$

Where,

$\Delta T$ = Change in Temperature

$C_p =$ Specific Heat

m = Mass

We can equate this equation and rearrange to find the change at the Temperature, then

$mgh = mC_p\Delta T$

$\Delta T = \frac{gh}{C_p}$

Our values are given as,

$C_p = 4186J/Kg\cdot K \rightarrow$ Specific Heat Water

Using energy conservation

$g = 9.8m/s^2$

$h = 807m$

Replacing,

$\Delta T = \frac{(9.8)(807)}{4186}$

$\Delta T = 1.89K$

Therefore the temperature increase in a 1kg sample of water is 1.89K

8 0

3 years ago

A world-class sprinter running a 100 m dash was clocked at 5.4 m/s 1.0 s after starting running and at 9.8 m/s 1.5 s later. In w

cupoosta [38]

Answer:

<em>The output power is greater in the interval from 1.0 s to 2.5 s</em>

Explanation:

<u>Physical Power </u>

It measures the amount of work W an object does in certain time t. The formula needed to compute power is

$\displaystyle P=\frac{W}{t}$

Work can be computed in several ways since we are given the motion conditions, we'll use this formula, for F= applied force, x=distance parallel to F

$W=F.x$

The second Newton's law gives us the net force as

$F=m.a$

being m the mass of the object and a the acceleration it has for a given period of time. In our problem, we have two different behaviors for each interval and we must calculate this force since the acceleration is changing. Let's calculate the acceleration in the first interval. We can use the formula for the final speed vf knowing the initial speed vo (which is 0 because the sprinter starts from rest), the acceleration a, and the time t:

$v_f=v_o+at$