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Ymorist [56]
3 years ago
15

How does erosion move and deposit rocks

Physics
1 answer:
Mashutka [201]3 years ago
5 0
Erosion, such as an expanding river, can move rocks to ocean or river beds by pushing them down steam. Erosion also slowly breaks down rocks so they slowly move down river and such in pieces, not a whole rock.
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Your tutor tells you that an ampere (A) and a volt (V) measure the same thing and that the different terms just make a simple co
saw5 [17]

Answer:

Explained

Explanation:

Your tutor is completely wrong here. Ampere and volt are both completely different concept. Ampere measure current in circuit, whereas volt measure the potential difference across two points in circuit. It is due to this difference in the potential that leads to flow of current in the circuit. The potential difference is the cause and current is the effect.

8 0
3 years ago
I'm looking at the barometer in my lab as i type this question. it says the pressure is 0.905 atm. what is this pressure express
Tcecarenko [31]
1 atm is equivalent to 760 torr.

To express 0.905 atm in torr, all you have to do is cross multiplication as follows:
1 atm ................> 760 torr
0.905 atm .........> ?? torr
pressure = (0.905 * 760) / (1) 
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4 0
3 years ago
if you look inside the bowl of a shiny metal spoon, your image is upside down. if you look at the outside of the bowl, your imag
vladimir2022 [97]
Because one side of the spoon is convex and the other side is concave, the spoon’s different sides reflect differently.
6 0
3 years ago
A gasoline tank has the shape of an inverted right circular cone with base radius 4 meters and height 5 meters. Gasoline is bein
RSB [31]

Answer:

h'=0.25m/s

Explanation:

In order to solve this problem, we need to start by drawing a diagram of the given situation. (See attached image).

So, the problem talks about an inverted circular cone with a given height and radius. The problem also tells us that water is being pumped into the tank at a rate of 8m^{3}/s. As you  may see, the problem is talking about a rate of volume over time. So we need to relate the volume, with the height of the cone with its radius. This relation is found on the volume of a cone formula:

V_{cone}=\frac{1}{3} \pi r^{2}h

notie the volume formula has two unknowns or variables, so we need to relate the radius with the height with an equation we can use to rewrite our volume formula in terms of either the radius or the height. Since in this case the problem wants us to find the rate of change over time of the height of the gasoline tank, we will need to rewrite our formula in terms of the height h.

If we take a look at a cross section of the cone, we can see that we can use similar triangles to find the equation we are looking for. When using similar triangles we get:

\frac {r}{h}=\frac{4}{5}

When solving for r, we get:

r=\frac{4}{5}h

so we can substitute this into our volume of a cone formula:

V_{cone}=\frac{1}{3} \pi (\frac{4}{5}h)^{2}h

which simplifies to:

V_{cone}=\frac{1}{3} \pi (\frac{16}{25}h^{2})h

V_{cone}=\frac{16}{75} \pi h^{3}

So now we can proceed and find the partial derivative over time of each of the sides of the equation, so we get:

\frac{dV}{dt}= \frac{16}{75} \pi (3)h^{2} \frac{dh}{dt}

Which simplifies to:

\frac{dV}{dt}= \frac{16}{25} \pi h^{2} \frac{dh}{dt}

So now I can solve the equation for dh/dt (the rate of height over time, the velocity at which height is increasing)

So we get:

\frac{dh}{dt}= \frac{(dV/dt)(25)}{16 \pi h^{2}}

Now we can substitute the provided values into our equation. So we get:

\frac{dh}{dt}= \frac{(8m^{3}/s)(25)}{16 \pi (4m)^{2}}

so:

\frac{dh}{dt}=0.25m/s

3 0
3 years ago
In chemistry, potential energy is usually considered to be the energy _____________.
Lunna [17]

Answer:

The answer is option D. Stored in the chemical bonds.

Hope it helps............

4 0
3 years ago
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