Friction = 0.25 * m * g = 10.8
Push = m * a + Friction = 4.4 * 1.5 + 10.8
Answer:
337.5m
Explanation:
<u>Kinematics</u>
Under constant acceleration, the kinematic equation holds:
, where "s" is the position at time "t", "a" is the constant acceleration, "
" is the initial velocity, and
is the initial position.
<u>Defining Displacement</u>
Displacement is the difference in positions:
or 



<u>Using known information</u>
Given that the initial velocity is zero ("skier stands at rest"), and zero times anything is zero, and zero plus anything remains unchanged, the equation simplifies further to the following:




So, to find the displacement after 15 seconds, with a constant acceleration of 3.0 m/s², substitute the known values, and simplify:

![\Delta s=\frac{1}{2}(3.0[\frac{m}{s^2}])(15.0[s])^2](https://tex.z-dn.net/?f=%5CDelta%20s%3D%5Cfrac%7B1%7D%7B2%7D%283.0%5B%5Cfrac%7Bm%7D%7Bs%5E2%7D%5D%29%2815.0%5Bs%5D%29%5E2)
![\Delta s=337.5[m]](https://tex.z-dn.net/?f=%5CDelta%20s%3D337.5%5Bm%5D)
The suns gravity pulls on the planets and keeps them in place. Its gravitational pull puts them in orbit around the sun
The right answer is B, the battery.
Answer:
Your little sister (mass 25.0 ) is sitting in her little red wagon (mass 8.50 at rest. You begin pulling her forward and continue accelerating her with a constant force for 2.35 at the end of which time she's moving at a speed of 1.80 .
(a) Calculate the impulse you imparted to the wagon and its passenger. (b) With what force did you pull on the wagon?