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Readme [11.4K]
3 years ago
5

An electric field of 710,000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of

-6.00 C at this spot? (14C - 10 6C) Give your answer in Si unit rounded to two decimal places
Physics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

4.26*10^6N

Explanation:

A charge within an electric field E experiences a force proportional to the field whose module is F = qE, whose direction is the same, if the charge is negative, it experiences a force in the opposite direction to the field and if the charge is positive, experience a force in the same direction of the field.

In our case we are interested in the magnitude of the force, therefore the sign of the charge has no relevance

\left | F \right |=\left |q  \right |  \left |E\right |\\\left | F \right |=6.00C*710000\frac{N}{C}=4.26*10^6N

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Answer:

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Synthesis reaction: two or more compounds combine to form one.

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Zepler [3.9K]

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Pls help :(( I need help!! Its physics! motion and forces!
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The reason I think this to be the answer to the analogy is because there is energy and work used in both processes (and the unit focuses on forces); gravity is constant and does not change whether one pedals or applies brakes. And I do not think it's deceleration, as deceleration tends to equate to acceleration within the physics perspective.

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