An electric field of 710,000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of
1 answer:
Answer:
Explanation:
A charge within an electric field E experiences a force proportional to the field whose module is F = qE, whose direction is the same, if the charge is negative, it experiences a force in the opposite direction to the field and if the charge is positive, experience a force in the same direction of the field.
In our case we are interested in the magnitude of the force, therefore the sign of the charge has no relevance
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Answer:
Explanation:
Gauge pressure at the bottom of the cylinder depends on the height of water in the cylinder
So here we can say that
now when liquid is filled to height "h" in base area "A" then gauge pressure of the liquid at the bottom is given as
now we put the whole liquid into another cylinder with twice radius of the first cylinder
So area becomes 4 times
now by volume conservation we can say that if area is increased by 4 times then height of liquid will decrease by 4 times
so we have
so gauge pressure is given as
Answer:
The charge on the capacitor had increased
Explanation:
The expression for the capacitance of an air-filled parallel-plate capacitor is as follows as;
Here, C is the capacitance, is the permittivity of free space, A is the area and d is the distance between the parallel plate capacitor.
When a slab of dielectric material is placed between the plates of the capacitor then the expression for the capacitance is as follows;
Here, K is the dielectric constant.
In the given problem, a slab is inserted between the plates of the capacitor then the capacitance of the capacitor will increase in this case. Therefore, the option (a) is true.
The expression for the charge stored in the capacitor is as;
Q= CV
Here, Q is the charge and V is the potential.
The charge will also increase in this case as the charge stored in the capacitor is directly proportional to the capacitance. Therefore, the option (d) is not true.
The expression for the energy stored in the capacitor is as follows;
The voltage is constant in the given problem but the capacitance increases then the energy stored in the capacitor will increase. Therefore, the option (b) is not true.
The voltage across the capacitor will remain same as the capacitor is still connected to the battery. Therefore, the option (c) is not true.
Therefore, only option (a) is true.