Answer:
The average kinetic energy of the system has increased as a result of the temperature increasing. 
Explanation:
Assuming this is a gas based on the framing. 
The molecules of a gas span a distribution of speeds, and the average kinetic energy of the molecules is directly proportional to the absolute temperature of the sample. KEavg is proportional to T.
This can be further studied until the Kinetic-Molecular Theory.
 
        
             
        
        
        
 
The volume of the flask would simply be equal to the
volume of the water. And the mass of the water would be the difference after
and before weigh.
mass of water = 489.1 g – 241.3 g
mass of water = 247.8 g
 
Therefore the volume of water (which is also the volume
of the flask) is:
volume = 247.8 g / (1.00 g/cm^3)
volume = 247.8 cm^3
 
The total mass of the flash when filled with chloroform
would be:
total mass with chloroform = 241.3 g + 247.8 cm^3 (1.48
g/cm3)
total mass with chloroform = 608.04 g
 
 
Answers:
volume = 247.8 cm^3
total mass with chloroform = 608.04 g
 
        
             
        
        
        
The answer for the following problem is mentioned below.
- <u><em>Therefore the final volume of the gas is 52.7 ml.</em></u>
 
Explanation:
Given:
Initial pressure (
) = 290 kPa
Final pressure (
) = 104 kPa
Initial volume (
) = 18.9 ml
To find:
Final volume (
)
We know;
From the ideal gas equation;
     P × V = n × R × T
where;
P represents the pressure of the gas
V represents the volume of gas 
n represents the no of the moles
R represents the universal gas constant 
T represents the temperature of the gas
So;
    P × V = constant 
    P ∝ 
From the above equation;
               
 represents the initial pressure of the gas 
 represents the final pressure of the gas
 represents the initial volume of the gas 
 represents the final volume of the gas
Substituting the values of the above equation;
                     
 = 
              
 = 52.7 ml
<u><em>Therefore the final volume of the gas is 52.7 ml.</em></u>
 
        
             
        
        
        
When mixture of NaCl and Al₂(SO₄)₃ is allowed to react with excess NaOH, only Al₂(SO₄)₃ reacts with it and NaCl does not react with NaOH due to presence of common ion (Na⁺). On reaction gelatinous precipitate of aluminium hydroxide [Al(OH)₃] is produced.  The balanced chemical reaction is represented as-
Al₂(SO₄)₃ + 6NaOH → 2Al(OH)₃ + 3Na₂SO₄ 
 On this reaction, 0.495 g = 0.495/78 moles =6.346 X 10⁻³ moles of Al(OH)₃.
As per balanced reaction, two moles of Al(OH)₃ is produced from one mole Al₂(SO₄)₃. So, 6.346 X 10⁻³ moles of Al(OH)₃ is produced from (6.346 X 10⁻³)/2 moles=3.173 X 10⁻³ moles of Al₂(SO₄)₃= 3.173 X 10⁻³ X 342 g of Al₂(SO₄)₃=1.085 g of Al₂(SO₄)₃.
So, mass percentage of Al₂(SO₄)₃ is= (amount of Al₂(SO₄)₃/total amount of mixture)X100 = 
 =74.8 %.