Answer:
1293000
Explanation:
1 metric tons are 1000000 grams
Current will be
![I=\dfrac{V_{rms}}{Z}=\dfrac{V_{rms}}{\sqrt{ R^{2}+(X_{C}-X_{L})^{2}}}\\where~X_{c}=\dfrac{1}{j.\omega .C}~and~X_{L}=j.\omega.L~where~\omega=2.\pi f~and~f=60Hz](https://tex.z-dn.net/?f=%20I%3D%5Cdfrac%7BV_%7Brms%7D%7D%7BZ%7D%3D%5Cdfrac%7BV_%7Brms%7D%7D%7B%5Csqrt%7B%20R%5E%7B2%7D%2B%28X_%7BC%7D-X_%7BL%7D%29%5E%7B2%7D%7D%7D%5C%5Cwhere~X_%7Bc%7D%3D%5Cdfrac%7B1%7D%7Bj.%5Comega%20.C%7D~and~X_%7BL%7D%3Dj.%5Comega.L~where~%5Comega%3D2.%5Cpi%20f~and~f%3D60Hz)
now just pluf in the values and Voila..
It is C) doing work because he is moving the bale of cotton.It only makes sense he is still doing work the pulley is just making it easier.
Answer:
Control of air–fuel ratio
Oxygen sensors tell the ECU whether the engine is running rich (too much fuel or too little oxygen) or running lean (too much oxygen or too little fuel) as compared to ideal conditions (known as stoichiometric).
Explanation:
The initial velocity of the ball is given as 36.0 m/s.
The horizontal component of velocity of ball is given as,
![v_x=v\cos \theta](https://tex.z-dn.net/?f=v_x%3Dv%5Ccos%20%5Ctheta)
The ball is projected vertically, therefore, the angle made by ball is 90 degree.
Plug in the known values,
![\begin{gathered} v_x=(36.0m/s)cos90^{\circ} \\ =(36.0\text{ m/s)(0)} \\ =0\text{ m/s} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20v_x%3D%2836.0m%2Fs%29cos90%5E%7B%5Ccirc%7D%20%5C%5C%20%3D%2836.0%5Ctext%7B%20m%2Fs%29%280%29%7D%20%5C%5C%20%3D0%5Ctext%7B%20m%2Fs%7D%20%5Cend%7Bgathered%7D)
Therefore, the initial horizontal velocity of ball is 0 m/s.
The vertical component of velocity of ball is given as,
![v_y=v\sin \theta](https://tex.z-dn.net/?f=v_y%3Dv%5Csin%20%5Ctheta)
Plug in the known values,
![\begin{gathered} v_y=(36.0m/s)\sin 90^{\circ} \\ =(36.0\text{ m/s)(1)} \\ =36.0\text{ m/s} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20v_y%3D%2836.0m%2Fs%29%5Csin%2090%5E%7B%5Ccirc%7D%20%5C%5C%20%3D%2836.0%5Ctext%7B%20m%2Fs%29%281%29%7D%20%5C%5C%20%3D36.0%5Ctext%7B%20m%2Fs%7D%20%5Cend%7Bgathered%7D)
Therefore, the initial vertical velocity of the ball is 36.0 m/s.