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iragen [17]
3 years ago
10

A stone is thrown vertically upward from the top of a platform with an initial velocity of 10m/s. Calculate the height of the pl

atform if it takes the stone 10secs to reach the ground. (g=10m/s2).​
Physics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

400 meters

Calculate how much time the stone take to achieve the highest point of its trajectory:

0 - 10 = -10 • t

-10 = -10t

t = -10/-10

t = 1

So, it took 1 second to achieve the highest point of trajectory. When the stone achieves it, its have velocity 0 and begin to fall, and it takes also 1 second to return to the top of the platform, so it means that during 2 seconds of the motion. The stone achieves the same high as the platform with the velocity of 10 m/s

Now let's calculate the distance its traveled to achieve the ground:

X = 10•8 + (10•8²)/2

X = 80 + 320

X = 400 meters

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meriva

Answer:

25m/s

Steps:

<em> First, The equation v= u + a * t shows us what we need to find, (the finale velocity). </em>

<em />

Second, we substitute the values given:

v= 9m/s + 4m/s2 * 4s

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Multiply 4m/s2 * 4s = 16m/s  

Add 9m/s + 16m/s

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Hope this helps :)

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Explanation:

3 0
2 years ago
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If two objects have the same mass, what determines the strength of the gravitational force between them? (4 points) Select one:
Evgen [1.6K]

According to this equation

F = G × m₁*m₂ ÷ r²

other than the mass, the distance also affects the gravitational force between two objects (same mass or not).

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3 years ago
A hot air balloon is traveling vertically upward at a constant speed of 4.5 m/s. When it is 28 m above the ground, a package is
ella [17]

Answer:

1.97 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow 21=4.5t+\frac{1}{2}\times -9.8\times t^2\\\Rightarrow 21=-4.5t-4.9t^2\\\Rightarrow 4.9t^2+4.5t-28=0\\\Rightarrow 49t^2+45t-280=0

Solving the above equation we get

t=\frac{-45+\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}, \frac{-45-\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}\\\Rightarrow t=1.97, -2.89

So, the time the package was in the air is 1.97 seconds

3 0
3 years ago
Answer and I will give you brainiliest <br><br><br><br><br>Please I need a surely answer ​
hichkok12 [17]

Answer:

<h2><u>Constant</u></h2>

Explanation:

Please don't comment in this question's comment box

<h2>Thanks</h2>
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