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iragen [17]
3 years ago
10

A stone is thrown vertically upward from the top of a platform with an initial velocity of 10m/s. Calculate the height of the pl

atform if it takes the stone 10secs to reach the ground. (g=10m/s2).​
Physics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

400 meters

Calculate how much time the stone take to achieve the highest point of its trajectory:

0 - 10 = -10 • t

-10 = -10t

t = -10/-10

t = 1

So, it took 1 second to achieve the highest point of trajectory. When the stone achieves it, its have velocity 0 and begin to fall, and it takes also 1 second to return to the top of the platform, so it means that during 2 seconds of the motion. The stone achieves the same high as the platform with the velocity of 10 m/s

Now let's calculate the distance its traveled to achieve the ground:

X = 10•8 + (10•8²)/2

X = 80 + 320

X = 400 meters

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What does the path of an object look like when it is in uniform motion?​
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1 year ago
Read 2 more answers
A rock climber hangs freely from a nylon rope that is 15 m long and has a diameter of 8.3 mm. If the rope stretches 5.1 cm, what
irinina [24]

Answer:

Mass of the climber = 69.38 kg

Explanation:

Change in length

        \Delta L=\frac{PL}{AE}

Load, P = m x 9.81 = 9.81m

Young's modulus, Y = 0.37 x 10¹⁰ N/m²

Area

       A=\frac{\pi (8.3\times 10^{-3})^2}{4}=5.41\times 10^{-5}m^2

Length, L = 15 m

ΔL = 5.1 cm = 0.051 m

Substituting

       0.051=\frac{9.81m\times 15}{5.41\times 10^{-5}\times 0.37\times 10^{10}}\\\\m=69.38kg  

Mass of the climber = 69.38 kg

6 0
3 years ago
A weightlifter presses a 200 N weight 0.5 m over his head in 2 s. What is the power of the weightlifter
icang [17]

Answer:

50 watts

Explanation:

Applying,

Power (P) = Workdone (W)/Time(t)

But,

Work done (W) = Force (F)×distance(d)

Therefore,

P = Fd/t..................... Equation 1

Where P =  power of the weightlifter, F = Force applied, d = distance, t = time.

From the question,

Given: F = 200 N, d = 0.5 m, t = 2 s

Substitute these values into equation 1

P = (200×0.5)/2

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P = 50 watts

7 0
2 years ago
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