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iragen [17]
3 years ago
10

A stone is thrown vertically upward from the top of a platform with an initial velocity of 10m/s. Calculate the height of the pl

atform if it takes the stone 10secs to reach the ground. (g=10m/s2).​
Physics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

400 meters

Calculate how much time the stone take to achieve the highest point of its trajectory:

0 - 10 = -10 • t

-10 = -10t

t = -10/-10

t = 1

So, it took 1 second to achieve the highest point of trajectory. When the stone achieves it, its have velocity 0 and begin to fall, and it takes also 1 second to return to the top of the platform, so it means that during 2 seconds of the motion. The stone achieves the same high as the platform with the velocity of 10 m/s

Now let's calculate the distance its traveled to achieve the ground:

X = 10•8 + (10•8²)/2

X = 80 + 320

X = 400 meters

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To solve this problem it is necessary to apply the kinematic equations of motion.

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For our case we have that there is neither initial position nor initial velocity, then

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With our values we have x = 401.4m, t=4.945s, rearranging to find a,

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