1.For the first ten reactions, write a balanced reaction for each tube in which a reaction occurred. If there was no reaction, w
1 answer:
The equations of reaction occurring in the tubes are as follows:
- 2 MnO₄⁻ + 6 Br⁻ + 8 H⁺ → 2 MnO₂ + 3 Br₂ + 4 H₂O
- 2 MnO₄⁻ + 6 I⁻ + 8 H⁺ → 2 MnO₂ + 3 I₂ + 4 H₂O
- No reaction
- 2 Fe³⁺ + 2 I⁻ → 2 Fe²⁺ + I₂
The reactions occurring in the tubes are redox reactions.
Based on the table the equations of reaction are as follows:
- 2 MnO₄⁻ + 6 Br⁻ + 8 H⁺ → 2 MnO₂ + 3 Br₂ + 4 H₂O
- 2 MnO₄⁻ + 6 I⁻ + 8 H⁺ → 2 MnO₂ + 3 I₂ + 4 H₂O
- No reaction
- 2 Fe³⁺ + 2 I⁻ → 2 Fe²⁺ + I₂
In conclusion, redox reaction are reactions in which electrons are transferred.
Learn more about redox reactions at: brainly.com/question/26750732
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The reaction between with calcium chloride can be shown as-
+
→
↓+2mCl. The molecular weight of
is 136.14g. The weight of sulfate ion is 96.06g. The molecular weight of
= (2×m + 96.06). From the reaction we can see that 1 mole of calcium chloride reacts with 1 moles
to produce 1 mole of calcium sulfate. Now 1.36g of calcium sulfate is equivalent to 1.36/136.14=9.989×
moles of calcium sulfate.
Thus, 9.989× moles of
reacts in this reaction.
Let assume the atomic mass of m is x thus the molecular weight of is 2x+96.
So we may write 9.989×× (2x+96) =1.42
Or, 2x + 96 = 142.146
Or, 2x = 46.146
Or, x = 23.073
Thus the atomic mass of m is 23.073. The atom (m) is sodium (Na).
Answer:
C. Plug the unknowns into the ideal gas law formula.
Explanation:
Gay-Lussac's law states that:
"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"
Mathematically, it can be written as:
where
p1 is the initial pressure
T1 is the initial temperature (in Kelvin)
p2 is the final pressure
T2 is the final temperature (in Kelvin)
Therefore, in order to solve for one of the 4 variables, the following steps must be adopted:
A. List your knowns and unknowns.
B. Convert temperature to kelvin.
D. Solve for the unknown.
While the following step is not needed:
C. Plug the unknowns into the ideal gas law formula.
Because we do not need to use the ideal gas law formula.
The question requires us to use the dilution formula , where
and
are the stock concentration and volume respectively, then
and
are the dilute concentration and volume respectively.
a. = 1.5 M KCI,
=0.20M KCl,
=250ml KCl
b.
To prepare the solution 33.3ml of 1.5M KCl is diluted to a total final volume of 250ml.