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kipiarov [429]
4 years ago
11

Which of the following transformations to ∆ABC would NOT preserve size and shape

Mathematics
1 answer:
Murrr4er [49]4 years ago
8 0

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, but I would show how to solve it.

Transformation is the movement of a point from its initial location to a new location. Transforming an object involves transforming all its points. Types of transformation is reflection, rotation, translation and dilation.

Rigid transformations are transformations that preserves the size and shape of an object. There are three types of rigid transformation which are:

  1. Rotation: This involves rotating a shape about a point.
  2. Reflection: This is the flipping of a shape across a line
  3. Translation: This is the sliding of an object up or down.

Dilation is the enlargement or reduction of shape of an object. Dilation is not a rigid transformation because it does not preserve the shape or size of the object.

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Rita works 1234 hours in her first week at a new job. She works 1514 hours in the second week. How many more hours does Rita wor
Sphinxa [80]

Answer:

280

Step-by-step explanation:

1514-1234 = 280

8 0
3 years ago
Points A B C D and E are collinear and in that order. Find AC if AE=x+50 and CE=x+32
Lana71 [14]

Answer:

18

Step-by-step explanation:

Points A B C D and E are collinear.

\therefore AE = AC + CE\\\therefore AC = AE - CE\\\therefore AC = x + 50 - (x + 32) \\\therefore AC = x + 50 - x - 32 \\\therefore AC =  50 - 32 \\ \huge \red{ \boxed{\therefore AC = 18}}

3 0
3 years ago
P(x)=x(x-5)(x-2)(x+3) what is the smallest zero
kolbaska11 [484]

Answer:

The smallest zero is -3.

Step-by-step explanation:

3 0
4 years ago
An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

800000\sqrt{(3 - d)^2 + 4}

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

800000\sqrt{(3 - d)^2 + 4} + 400000d

We can find the minimum value of this by taking the 1st derivative and set it to 0

800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0

We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

\sqrt{(3 - d)^2 + 4} = 6 - 2d

From here we can square up both sides

(3 - d)^2 + 4 = (6 - 2d)^2

9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

3d^2-18d+27 = 0

d^2 - 6d + 9 = 0

(d - 3)^2 = 0

d -3 = 0

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0
3 years ago
Help me with only #10-14 please ????
HACTEHA [7]
#10 - 64°
#11 - 67°
#12 - 42in.
#13 - 45.5in.
#14 - i think it's 133.5 but i'm not sure.
4 0
3 years ago
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