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Alex_Xolod [135]
3 years ago
11

For a moving object, the force acting on the object varies directly with the objects acceleration. When a force of 24N acts on a

certain object, the acceleration of the object is 3m/s^2. If the acceleration of the object becomes 10m/s^2, what is the force
Physics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

80 N

Explanation:

From the question,

F = ma .......................... Equation 1

Where F = Force, m = mass of the object, a = acceleration of the object.

make m the subject of the equation

m = F/a.................... Equation 2

Given: F = 24 N, a = 3 m/s²

Substitute into equation 2

m = 24/3

m = 8 kg.

If the acceleration of the object becomes 10 m/s²,

Substitute into equation 1

F = 10(8)

F = 80 N.

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Answer;

B. both a non-directional and directional hypothesis

Explanation;

A two-tailed test is the standard test of significance to determine if there is a relationship between variables in either direction. Two-tailed tests do this by dividing the .05 in two and putting half on each side of the bell curve.

A non-directional hypothesis is a type of alternative hypothesis used in statistical significance testing. In contrast, a directional alternative hypothesis specifies the direction of the tested relationship, stating that one variable is predicted to be larger or smaller than null value, but not both.


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3 years ago
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Work out the kinetic energy of a 2.5 kg remote-controlled car that is moving at 2 m/s.
lbvjy [14]

Answer: 5 joules

Explanation:

mass=m=2.5kg

Velocity=v=2m/s

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ke=(m x v x v)/2

ke=(2.5 x 2 x 2)/2

Ke=10/2

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3 years ago
You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo
S_A_V [24]

Answer:

A.  Z = 185.87Ω

B.  I  =  0.16A

C.  V = 1mV

D.  VL = 68.8V

E.  Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

Z=\sqrt{R^2+\omega^2L^2}       (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

I=\frac{V}{Z}                     (2)

V: voltage amplitude = 30.0V

I=\frac{30.0V}{185.87\Omega}=0.16A

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV            (3)

D. The voltage across the inductor is:

V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V

E. The phase difference is given by:

\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°

5 0
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Answer:

B. In the same group

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