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Alex_Xolod [135]
3 years ago
11

For a moving object, the force acting on the object varies directly with the objects acceleration. When a force of 24N acts on a

certain object, the acceleration of the object is 3m/s^2. If the acceleration of the object becomes 10m/s^2, what is the force
Physics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

80 N

Explanation:

From the question,

F = ma .......................... Equation 1

Where F = Force, m = mass of the object, a = acceleration of the object.

make m the subject of the equation

m = F/a.................... Equation 2

Given: F = 24 N, a = 3 m/s²

Substitute into equation 2

m = 24/3

m = 8 kg.

If the acceleration of the object becomes 10 m/s²,

Substitute into equation 1

F = 10(8)

F = 80 N.

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The flow control circuit design that can best control an overrunning load is the ____ circuit.
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A 5.00-m-long uniform ladder, weighing 200 N, rests against a smooth vertical wall with its base on a horizontal rough floor, a
Morgarella [4.7K]

Answer:

0.488  m  

Explanation:

If θ be the angle ladder makes with the plane

cos θ = 1.2 / 5

Tan θ = 4.04

Let the height a person of weight 600 N  can climb be h from the ground .

Distance from the base point  where ladder touches the floor  = h / tanθ

= h / 4.04

Total reaction force = total downward force

R = 200 + 600

800 N

Frictional force = μ R

= .2 x 800

= 160 N

Taking moment of force about the point on the ladder  where it  touches the floor  and balancing them

200 x 1.2 x .5 + 600 x   h / tanθ  = μ R x  1.2 / tanθ ( reaction  at the top point of ladder where it touches the wall is  R₁ and

R₁ =μ R   )

= 200 x 1.2 x .5 + 600 x   h / tanθ  = 160 x 1.2 / tanθ

120  - 600 h / 4.04 = 47.52

120 - 47.52 = 600 h / 4.04

72.48= 148.51 h

h = 0.488  m  

=

5 0
3 years ago
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